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mel-nik [20]
3 years ago
8

HURRY PLEASEE!!!! TAKING AN EXAM !! AND ITS TIMED!!! WILL GIVE BRAINLIEST!!

Mathematics
2 answers:
Margaret [11]3 years ago
7 0

Answer:

(x,y) --> (x+7, y-6)

Step-by-step explanation:

Good luck with your exam! :DD

worty [1.4K]3 years ago
4 0

Answer:

B (x+7, y-6)

Step-by-step explanation:

It goes right 7 and down 6

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A roll of paper towels contained 250 sheets. Each sheet was 8.75 inches long. How long was the roll?
aliya0001 [1]
250 × 8.75 = 2187.5 inches long
3 0
3 years ago
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En el pequeño frasco se colocaron 7 galletas para regalar si ornearon 56 ¿cuantos frascos. regalaron?​
Solnce55 [7]

Answer:

1 frasco

Step-by-step explanation:

En el pequeño frasco se colocaron 7 galletas para regalar si ornearon 56 ¿cuantos frascos. regalaron?

8 0
3 years ago
Better Products, Inc., manufactures three products on two machines. In a typical week, 40 hours are available on each machine. T
Kaylis [27]

Answer:

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

Step-by-step explanation:

                                Profit $    mach. 1      mach. 2

Product 1     ( x₁ )       30             0.5              1

Product 2    ( x₂ )       50             2                  1

Product 3    ( x₃ )       20             0.75             0.5

Machinne 1 require  2 operators

Machine   2 require  1  operator

Amaximum of  100 hours of labor available

Then Objective Function:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Constraints:

1.-Machine 1 hours available  40

In machine 1    L-H  we will need

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

2.-Machine 2   hours available  40

1*x₁  +  1*x₂   + 0.5*x₃   ≤  40

3.-Labor-hours available   100

Machine 1     2*( 0.5*x₁ +  2*x₂  +  0.75*x₃ )

Machine  2       x₁   +   x₂   +  0.5*x₃  

Total labor-hours   :  

2*x₁  +  5*x₂  +  2*x₃  ≤  100

4.- Production requirement:

x₁  ≤  0.5 *( x₁ +  x₂  +  x₃ )     or   0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

5.-Production requirement:

x₃  ≥  0,2 * ( x₁  +  x₂   +  x₃ )  or    -0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

General constraints:

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

The model is:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Subject to:

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

1*x₁  +  1*x₂   + 0.5*x₃       ≤  40

2*x₁  +  5*x₂  +  2*x₃        ≤  100

0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

-0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

After 6 iterations with the help of the on-line solver AtomZmaths we find

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

6 0
3 years ago
What do i do next please
emmasim [6.3K]
Now subtract, then add.
4 - 2 = 2 then add 12. 
2 + 12 = 14.

Answer is 14.
4 0
3 years ago
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Do you think inequalities or equations are used more in everyday life? Justify your answer. In your answer include literal equat
nevsk [136]
Yes, I do think that inequalities or equations are used more in everyday life.
5 0
3 years ago
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