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2 years ago

Which of the following shows the function f (x) being translated 4 units up?

Mathematics

1 answer:

Shtirlitz [24]2 years ago

3 0

Answer:

where is the following

Step-by-step explanation:

b i can teve n tse the following answers

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How do I write 16,107,320 in expanded form?

Pani-rosa [81]

In expanded form that would be 10,000,000 + 6,000,000 + 100,000 + 7,000 + 300 + 20

3 0

2 years ago

What are the first three terms of the sequence defined by the recursive function an=an-1-(an-2-4), when a5=-2 and a6=0

BaLLatris [955]

Answer:

6, 10, 8

Step-by-step explanation:

aₙ= aₙ₋₁ - (aₙ₋₂ - 4)= aₙ₋₁ - aₙ₋₂ + 4

a₅= -2

a₆= 0

-----------

aₙ₋₂= aₙ₋₁ - aₙ + 4

a₄= a₅- a₆ + 4 = -2 - 0 + 4 = 2
a₃= a₄ - a₅ + 4 = 2 - (-2) + 4 = 8
a₂= a₃ - a₄ + 4 = 8 - 2 + 4 = 10
a₁= a₂ - a₃ + 4 = 10 - 8 + 4 = 6

The first 3 terms: 6, 10 and 8

4 0

2 years ago

Please help! Thanks.

Karo-lina-s [1.5K]

Answer:

because it has the same angle

6 0

3 years ago

Read 2 more answers

Solve by graphing -3x + y = 4 y = -2x - 1

Dafna11 [192]

Answer:

(-1,1)

Step-by-step explanation:

6 0

2 years ago

A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

mojhsa [17]

Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, MOE = 0.04.

The formula for margin of error is:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}$

The critical value of z for 95% confidence interval is: $z_{\alpha/2}=1.96$

Compute the minimum sample size required as follows:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601$

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, MOE = 0.02.

The formula for margin of error is:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}$

The critical value of z for 95% confidence interval is: $z_{\alpha/2}=1.96$

Compute the minimum sample size required as follows:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.02}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=2401.00\approx 2401$

Thus, the minimum sample size required achieve a margin of error of 0.02 is 2401.

8 0

3 years ago