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nadya68 [22]
3 years ago
14

Which shows where the function is increasing?

Mathematics
1 answer:
V125BC [204]3 years ago
4 0

Answer:

In zone A and zone E.

Step-by-step explanation:

See the attached graph to this question.

The graph clearly shows that the function is increasing in the portion which is denoted by A and E.

In the A zone, the graph moves from minima towards local maxima and in the E zone, the graph moves from a local minima towards maxima.

In both the zones, the value of f(x) increases as the value of x increases. Therefore, the function is increasing in A and E zone. (Answer)

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If the 6th term of an A.P. is 46, find the sum of first 11 terms.​
zaharov [31]

Answer:

506

Step-by-step explanation:

:. t6 = 46 ... [ Given ]

tn = a+(n-1) d ... [ Formula ]

:. t6 = a+(6-1) d

:. 46 = a+5d ... [1]

Sn = n/2 [2a+(n-1)d] ... [ Formula ]

:. S11 = 11/2 [2a+(11-1) d]

:. S11 = 11/2 [2a+10d]

:. S11 = 11/2x2 [a+5d]

:. S11 = 11[46] ... [ From (1)]

:. S11 = 506

5 0
3 years ago
Mrs. Rogers sold 49 out of 78 crafts at the fair. What percent of her crafts did she sell? Show your
igor_vitrenko [27]

Answer:

62.8, 63% if you around it off.

Step-by-step explanation: Do 49 Divided by 78, then times it by 100 to get your percentage. I just rounded it off to the nearest tenth and whole number just in case. Hope this helped!

3 0
2 years ago
The population of a city is expected to
Furkat [3]

\huge\boxed{1.0925p}

Since the population is going to increase by a certain percentage, we have to add 100\% to the percentage to keep the original population.

9.25\%+100\%=109.25\%

Now, convert the percentage into a decimal. You can do this by moving the decimal place two places to the left.

109.25\longrightarrow 1.0925

Now, just multiply that by p.

\large\boxed{1.0925p}

8 0
3 years ago
Which relation is also a function?
ratelena [41]

Answer:

{ (0, 0), (4, 0), (6, 0) }

Step-by-step explanation:

In order to be a function, ordered pairs must have values of x, or the domain, that are different and do not repeat.

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