$\left( \dfrac 49 \right) \div \left( \dfrac{18} 3 \right)\\\\\\=\dfrac 49 \div6\\\\\\=\dfrac 49 \times \dfrac 16\\\\\\=\dfrac{2}{9\times 3}\\\\\\=\dfrac{2}{27}$

6 0

2 years ago

The coldest temperature one day was -10°F. during the day the temperature climbed 16°. what was the higher temperature?

Tom [10]

If it was -10 degrees outside and it went up 16 degrees then it would be 5 degrees outside

4 0

3 years ago

Someone help me pls

FrozenT [24]

Answer:

i can np

Step-by-step explanation:

6 0

3 years ago

PLLLLLLLSSSS HELP MMEEEEEE 30 pointsssss

icang [17]

Answer:

So you take 3.4 and subtract from 6.6 which equals 3.2. Then if you add 3.4+3.2= 6.6. Hope this helps.

Step-by-step explanation:

8 0

3 years ago

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