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2 years ago

Every orthogonal matrix is diagonalizable. O True O False

Mathematics

1 answer:

Simora [160]2 years ago

5 0

Answer:

FALSE

Step-by-step explanation:

the correct answer is FALSE

A matrix is said to be orthogonal when it is multiplied by its own transpose then the matrix comes out to be Identity.

$A^T.A = I$

the basic condition for a matrix to be diagonalizable is that the matrix should be symmetric.

but an orthogonal matrix is not necessarily symmetric so, the statement is false.

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Bella had already read 20% of the book before her teacher assigned it to the class. She is choosing between two options to finis

Lubov Fominskaja [6]

Answer:

How big is the book?

If it has more than 96 pages remaining 25% each night is quicker if it has less that 96 or less remaining 24 pages a night is faster

Step-by-step explanation:

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3 years ago

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X +5+11x=12x+Y It says find the value of y that makes each equation true for all values of

sladkih [1.3K]

X + 5 + 11x = 12x + y

Simplify: 12x + 5 = 12x + y (We are adding x and 11x on the left side)

Subtract 12x from each side makes each zero.

5 = y

So we can plug in and test. I'm picking two random numbers to plug in for x. 10, and 82

x = 10, y = 5
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2 years ago

The air temperature in the North Pole in the morning was 3 degrees Celsius. By 10:00 am the temperature dropped 12 degrees. By n

WINSTONCH [101]

Answer: -11 degrees Celsius

Step-by-step explanation:

First you subtract 3-12 leaving -9 then you add positive 5 to -9 giving you -4 then add 9 to equal 5 and lastly 5- 16 to get -11.

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2 years ago

Neptune is an average distance of 4.5 × 10^9 km from the Sun. Estimate the length of the Neptunian year using the fact that the

zlopas [31]

Answer:

164.32 earth year

Step-by-step explanation:

distance of Neptune, Rn = 4.5 x 10^9 km

distance of earth, Re = 1.5 x 10^8 km

time period of earth, Te = 1 year

let the time period of Neptune is Tn.

According to the Kepler's third law

T² ∝ R³

$\left ( \frac{T_{n}}{T_{e}} \right )^{2}=\left ( \frac{R_{n}}{R_{e}} \right )^{3}$

$\left ( \frac{T_{n}}{1} \right )^{2}=\left ( \frac{4.5\times10^{9}}}{1.5\times10^{8}}} \right )^{3}$

Tn = 164.32 earth years

Thus, the neptune year is equal to 164.32 earth year.

Step-by-step explanation:

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3 years ago

PLEASE HELP!! will be marked brainliest!!

Arturiano [62]

Answer:

yup and yup

Step-by-step explanation:

also 1. is yup and yup

7 0

2 years ago

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