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Tresset [83]
3 years ago
13

the length of the rectangle is x + 10 the width of the rectangle is x +2 please determine the area of the rectangle. you may sho

w your work using the box method or you may show your work algebraically (distribution or foil). make sure your answer is written in simplest form
Mathematics
2 answers:
poizon [28]3 years ago
5 0
A = lw
A = (x+10)(x+2)
A = x^2+2x+10x+20
A = x^2+12x+20
Vladimir79 [104]3 years ago
5 0

Answer:

A = lw

A = (x+10)(x+2)

A = x^2+2x+10x+20

A = x^2+12x            +20

Have a nice day.

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8 0
3 years ago
Evaluate x + y when x = - 18.2 and y = 3.6
Contact [7]
-18.2 + 3.6= -14.6 is the answer to the question
3 0
3 years ago
Read 2 more answers
Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0
3 years ago
Read 2 more answers
Can I get help with these too? Thank you!!!!!
Anastasy [175]
For ABC:

The interior angle of C is 180 - 142 = 38
The three interior angles add up to 180°
(2x - 15) + (x - 5) + 38 = 180
3x - 20 + 38 = 180
3x + 18 = 180
3x = 162
x = 54

The measure of angle ABC = x - 5 = 54 - 5 = 49

For JKL:
The interior angle of L is 180 - 100 = 80°
The 3 interior angles add up to 180°
(2x + 27) + (2x - 11) + 80 = 180
4x + 16 + 80 = 180
4x + 96 = 180
4x = 84
x = 21

The measure of angle JKL is 2x - 11 = 2(21) - 11 = 42 - 11 = 31°
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Find the m TFS.<br><br>Answer choices are:<br>12 degrees<br>76 degrees<br>64 degrees<br>52 degrees​
goblinko [34]
It’s 52 because there are two sides with 64 degrees (the bottom two sides) and you add those to sides together and subtract your combine angle of the bottom 2 sides by 180 degrees which is the degree of all triangles combine and get 52
4 0
3 years ago
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