If you notice, the container is really just two circles, with a diameter of 4 each, and a square with sides of 10.5.
now, if we just get the area of each circle, keeping in mind their radius is half of the diameter, namely r = 2, and get the area of the 10.5x10.5 square, sum them up, that'd be the surface area of the container.
Solution:
Rewrite 3 ≥ y - 2 for easier calculation:
y - 2 ≤ 3
Move the term:
y ≤ 3 + 2
y ≤ 5
When graphing the solution, filled dot (black arrow) is used for ≤ and ≥ while empty dot (white arrow) is used for < >
Okay so we get: subtract m + 8 from 5m + 11
5m + 11 = 16 + m or 16m
16m - 8 +m or 8m = 8m or 8 + m
C ⠀ ⠀ ⠀ ⠀ ⠀
The points between 0 and 1 increase in increments of 1/6th
Try this option:
1. Common view of hyperbola equation is:
2. hyperbolas are: 2x²+4x-5y²-10y+57=0 and -x²+12x+3y²+7y+11=0.