All categories

2 years ago

Find the measure of y in the drawing. 51° 129° 61° 139°

Mathematics

2 answers:

alukav5142 [94]2 years ago

5 0

Answer:

B) y = 129º

Step-by-step explanation:

since a triangle is 180º in total, the you have to subtract 71 and 58 from 180 which will give you 51º which gives you the amount for x

and the line that the triangle is on is also 180º in total, so you subtract the 51 from 180 to give you a total of 129º which is the amount for y

snow_lady [41]2 years ago

4 0

Answer:

B) y = 129º

Step-by-step explanation:

since a triangle is 180º in total, the you have to subtract 71 and 58 from 180 which will give you 51º which gives you the amount for x

and the line that the triangle is on is also 180º in total, so you subtract the 51 from 180 to give you a total of 129º which is the amount for y

You might be interested in

Does anyone know the answer

vladimir1956 [14]

Answer:

yes me

Step-by-step explanation:

na jp ion know

3 0

2 years ago

On a number line, which number is 7/9 of the way from -6 to 3

Paha777 [63]

Answer:

Step-by-step explanation:

if you go from -6 to 3 it is 9 spaces. so 7 spaces equals one.

4 0

3 years ago

What is the general form of the equation of the line shown?

ZanzabumX [31]

Check the picture below. So let's use those two points on the line.

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{3}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{3-0}{3-0}\implies \cfrac{3}{3}\implies 1 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-0=1(x-0)\implies y=x \\\\\\ -x+y=0\implies \stackrel{\textit{standard form}}{x-y=0}$

bearing in mind that the standard form is also a general form.

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

5 0

3 years ago

Read 2 more answers

Which is equivalent to sin^-1(tan(pi/4)) ? Give your answer in radians.

aleksklad [387]

We are to find the value of $sin^{-1}(tan( \frac{ \pi }{4}))$

First we evaluate tan(π/4). The value of tan(π/4) is 1.

So,

$sin^{-1}(tan( \frac{ \pi }{4})) =sin^{-1} (1)$

sin(π/2) = 1
So,
$sin^{-1}(1)= \frac{ \pi }{2}$

Thus, we can write:

$sin^{-1}(tan( \frac{ \pi }{4}))= \frac{ \pi }{2}$ radians.

So, the answer to this question is π/2 radians.

6 0

2 years ago

Read 2 more answers

Edmond buys 4/5 of a kilogram of butterscotch chips and 5 kilograms of milk chocolate chips.

Vika [28.1K]

He spent $5.80.

1 x 4/5 = 0.8
1 x 5 = 5

8 0

2 years ago