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2 years ago

A number that will exceed the unknown number by 5

Mathematics

1 answer:

lora16 [44]2 years ago

6 0

Step-by-step explanation:

click on the image for the full answer

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CAN ANYONE DO IT PLZ.

docker41 [41]

<u>Answer: </u>120

Since there is the 100 in the triangle, the other two sides in the triangle are equal to each other. So they are both 40

So 180 - 40 = 120

6 0

2 years ago

Read 2 more answers

PTG has side lengths of 18 cm, 27 cm, and 13 cm. which type of triangle is PTG? The answer is obtuse.

Verizon [17]

To know what kind of triangle is it. use the pythagorean theorem:
A^2 + B^2 = C^2,
where C is the longest side of the triangle
if it satisfies the equation then it is a right triangle
if it does not then A^2 + B^2 > C^2 so it is acute triangle
if A^2 + B^2 < C^2 it is obtuse triangle

18^2 + 13^2 ? 27^2
324 + 169 ? 729
493 < 729 so it is obtuse triangle

3 0

2 years ago

58-(1/4)2 i dont get how to solve this

xeze [42]

Answer:

57.5

Step-by-step explanation:

First you would have to multiply following PEMDAS so

(1/4)(2)

=0.5

Then subtract 58 and 0.5

58-0.5

=57.5

and thats your answer

5 0

2 years ago

Read 2 more answers

5.) A car dealership has hired you to determine how many sales they can make based on how many flash sales they have in a quarte

Step2247 [10]

Answer:

its B

Step-by-step explanation:

sorry if its wrong

5 0

2 years ago

A magazine currently has 8700 subscribers for its online web version. It is adding members at the rate of R(t) = 190e0.03t subsc

aleksklad [387]

Number of subscriber the magazine will have after 3 years from now approximately be 8767

<u>Solution:</u>

Given that magazine currently has 8700 subscribers for its online web version

$\begin{array}{l}{\mathrm{R}(\mathrm{t})=190 \mathrm{e}^{0.03 \mathrm{t}} \text { subscribers/month }} \\\\ {\mathrm{S}(\mathrm{t})=\mathrm{e}^{-0.06 \mathrm{t}}}\end{array}$

After 3 years, time(t) = 36 month

Total number of subscribers after 3 years from now :

Substitute "t" = 36

$\begin{array}{l}{\mathrm{R}(36)=190 \mathrm{e}^{0.03 \times(36)}=190 \times(2.944)} \\\\ {\mathrm{R}(36) \approx 560} \\\\ {\mathrm{S}(36)=\mathrm{e}^{-0.06 \times(36)}=0.12}\end{array}$

Subscribers remaining = 0.12 x 560 = 67.2

The magazine currently has 8700 subscribers

Added Subscriber = 8700 + 560 = 9260

Remaining Subscriber = 8700 + 67.2 = 8767.2

Therefore number of subscriber the magazine will have after 3 years from now approximately be 8767

7 0

3 years ago