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3 years ago

A number that will exceed the unknown number by 5

Mathematics

1 answer:

lora16 [44]3 years ago

6 0

Step-by-step explanation:

click on the image for the full answer

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Which ordered pair is a solution of the system of equations? y= 3x + 1 y= 5x - 1 A (2,3) © (1,2) B (0, 1) D (1,4)

Vadim26 [7]

Answer:

Step-by-step explanation:

So first, we have to test the pairs. Let start with equation 1.

7=\=3 x

4=\=2 x

0=0 ✓

4=4 ✓

Now we only have to test B and D.

0=\=-1

4=4 ✓

D is the correct answer.

7 0

3 years ago

The price of a technology stock was $9.74 yesterday. Today, the price fell to $9.67. Find the percentage decrease. Round your an

agasfer [191]

% change = (new value - old value)/(old value) * 100%
.. = (9.67 -9.74)/9.74 * 100%
.. = -0.07/9.74 * 100%
.. = -0.7%

The decrease is 0.7%.

5 0

3 years ago

Find the area of a triangle with legs that are: 6 mm, 4 mm, and 8 mm.

Musya8 [376]

Hence,the option is B. If you have any doubts plzz lemme know.

6 0

3 years ago

which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

6 0

3 years ago

2/9 of students in a school are in sixth grade.

Triss [41]

There are 42 students in sixth grade.

6 0

3 years ago