The answer to your question 4x-4y= -2 plus -9x-4y= -3 is -5 because in order to find the result of the two equations would be to add the solutions to both of them together.
Answer and Step-by-step explanation:
we have the following data:
Point estimate = sample mean = \ bar x = 12.39
Population standard deviation = \ sigma = 3.7
Sample size = n = 177
a) the margin of error with a 90% confidence interval
α = 1 - 90%
alpha = 1 - 0.90 = 0.10
alpha / 2 = 0.05
Z \ alpha / 2 = Z0.05 = 1,645
Margin of error = E = Z \ alpha / 2 * (\ sigma / \ sqrtn)
we replace:
E = 1.645 * (3.7 / \ sqrt177)
Outcome:
E = 0.46
b) margin of error with a 99% confidence interval
α = 1-99%
alpha = 1 - 0.99 = 0.01
alpha / 2 = 0.005
Z \ alpha / 2 = Z0.005 = 2,576
Margin of error = E = Z \ alpha / 2 * (\ sigma / \ sqrtn)
we replace:
E = 2,576 * (3.7 / \ sqrt177)
Outcome:
E = 0.72
c) A larger confidence interval value will increase the margin of error.
Answer:
x^4 + 5x^3 - 12x^2 + 5x + 1
Answer:
No, the maximum height that the balloon can reach is 9ft.
Step-by-step explanation:
Hi, to answer this question we have to analyze the information given:
The function h(x) =-0.5(x-4)² +9, is a Quadratic Function in the Vertex form.
Vertex form: f (x) = a(x - h) 2 + k
Where:
- (h, k) is the vertex of the parabola-
- h is the horizontal shift (how far left, or right, the graph has shifted from x = 0).
- k represents the vertical shift (how far up, or down, the graph has shifted from y = 0).
In this case a = -0.5, it means that the parabola opens downward and has a maximum point at the vertex.
So, the maximum height that the balloon can reach is k=9ft.
9 ∠ 12
The balloon will not hit the ceiling 12 ft above the pool.
Feel free to ask for more if needed or if you did not understand something.
4(m + 2) expanded is 4 x m and 4 x 2
simplified: 4m + 8