To find the answer to this problem, you just need to figure out which total amount of candy is divisible by 7.
161/7=23
<span>162/7=23.1428571429
</span>145/7=<span>20.7142857143
128/7=</span><span>18.2857142857
Obviously, Julie cannot give a fraction of an amount of candy to someone. So that rules out that she had 162, 145, or 128 pieces of candy.
The only amount of candies that Julie could have that is divisible by 7 is 161 candies, which means that 161 is your answer.</span>
Transmission must be in third gear as both are running at the same speed ! so third gear !!!
If you know the formular a^3+b^3=(a+b)(a^2-ab+b^2), you can solve this problem.
8 is 2 cubed, so x^3+2^3=(x+2)(x^2-2x+4)
so the other quadratic factor is x^2-2x+4
Answer: the system has no solution
Step-by-step explanation: for a solution to occur the lines have to cross
