Using Keplers Law, T is proportional to r^ (3/2)
T^2 is proportional to r^3
[Tj / Te]^2 = [rj / re]^3
=> Tj^2 = [rj / re]^3 x Te^2
=> Tj^2 = [5.2 / 1.0]^3 x (1.0)^2
=> Tj^2 = 140.6 => Tj = squareroot of 140.608
=> Tj = 11.85 year, which is approximately 12 years
So the Jupiters orbital period in Earth years is 12 years.
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ack i think so...
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