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3 years ago

If Polly decides to slice each pizza into 10 equal slices, how much of the pizza is each slice in decimal form?

Mathematics

1 answer:

evablogger [386]3 years ago

5 0

Answer:

0.10

Step-by-step explanation:

some idiot deleted my answer lol

to do this you divide the total whole by the pieces you want . So 1/10=0.10

and thats your answer and how to get it :)

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I am in a subset of rational numbers, I am not negative, I am a whole number, I am not a natural number, what number am I?

MakcuM [25]

Answer:

Step-by-step explanation:

0 is considered a whole number, but it is not a natural number. The natural numbers start at +1 and go forward. ) is not positive or negative, but being that it is a whole number, it is also a rational number.

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3 years ago

5 cooks, 13 waiters and 4 other staff work at a restaurant. What is the ratio of cooks to waiters to other staff?

devlian [24]

Answer:

1:4:1.5

Step-by-step explanation:

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3 years ago

What are 2 multiplication expressions that have the product of 28.34 ?!?!?!? NEED HELP ASAP!!!!

Elodia [21]

Answer:

14.17x2 and 7.085x4

Step-by-step explanation:

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3 years ago

I don’t get this, can you guys help out?

Dovator [93]

Answer:

9 ÷ 3/2 = 6

21 ÷ 7/3 = 9

12/7 ÷ 2/7 = 6

4 2/3 ÷ 7/9 = 6

72/7 ÷ 8/7 = 9

4 1/2 ÷ 1/2 = 9

4 0

3 years ago

Read 2 more answers

Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th

denpristay [2]

Answer:

(1) Correct option is B.

(2) Correct option is C.

Step-by-step explanation:

The information provided is:

$n_{1}=200,\ \bar x_{1}=22.7,\ s_{1} = 4.5\\n_{2}=200,\ \bar x_{2}=19.7,\ s_{2} = 4.3$

The (1 - <em>α</em>)% confidence interval for the difference between two mean is:

$CI=\bar x_{1}-\bar x_{2}\pm t_{\alpha/2, (n_{1}+n_[2}-2}\sqrt{\frac{s_{1}^{2}}{n_{1}}+\frac{s_{2}^{2}}{n_{2}} }$

The critical value of <em>t</em> is:

$\alpha /2=0.05/2=0.025$

degrees of freedom $=n_{1}+n_{2}-2=200+200-2=398$

$t_{\alpha/2, n_{1}+n_{2}-2}=t_{0.025, 398}=1.96$

Compute the 95% confidence interval for the difference between two mean as follows:

$CI=22.7-19.7\pm 1.96\sqrt{\frac{4.5^{2}}{200}+\frac{4.3^{2}}{200} }\\=3\pm0.8624\\=(2.1376, 3.8624)\\\approx(2.14, 3.86)$

Thus, the 95% confidence interval, (2.14, 3.86) implies that the true mean difference value is contained in this interval with probability 0.95.

Correct option is B.

The null value of the difference between means is 0.

As the value 0 is not in the interval this implies that there is a difference between the two means, concluding that priming does have an effect on scores.

Correct option is C.

4 0

3 years ago