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fgiga [73]
3 years ago
9

Linear Equations. Solve the equation 5 = 3y +6 using inverse operations.

Mathematics
1 answer:
agasfer [191]3 years ago
4 0

Answer:

The value of y=\frac{-1}{3}.

Step-by-step explanation:

Considering the equation

5 = 3y +6

To solve the equation 5 = 3y +6 using inverse operations,

Subtracting 6 on both sides of the equation,

5-6 = 3y +6-6

Simplifying,

-1 = 3y

Dividing both sides by 3

\frac{-1}{3} =\frac{3y}{3}

\frac{-1}{3} =y

Switching both sides

y=\frac{-1}{3}

Therefore, the value of y=\frac{-1}{3}.

Keywords: equation, inverse operations

Learn more about equation, inverse operations from brainly.com/question/14623363

#learnwithBrainly

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Answer:

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Three years ago Tom was twice as old as Jean, and in two years the sum of their ages will be 28 years. Find their present ages.
lubasha [3.4K]

Answer:

Jean is 9 and Tom is 15.

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The television show 50 Minutes has been successful for many years. That show recently had a share of 29, meaning that among the
BigorU [14]

Answer:

(a) P (none) = 0.005873

(b) P ( at least one household ) = 0.9941

(c) P ( at most one household )  = 0.9960

(d) not wrong

Step-by-step explanation:

Given data

probability P = 29%  = 0.29

no of sample n = 15

tv show  X = 50

to find out

the probability that none of the households

the probability that at least one household

the probability that at most one household

If at most one household is tuned to 50 Minutes, does it appear that the 19% share value is wrong

solution

the probability that none of the households is tuned to 50 Minutes is

P (none) = 10C0 × P^{0}  ×  (1 - 0.29)^{15}

P (none) =  (0.71)^{15}

P (none) = 0.005873

and the probability that at least one household is tuned to 50 Minutes is

P ( at least one household ) = 1 - P(none)

P ( at least one household ) = 1 - 0.005873

P ( at least one household ) = 1 - 0.005873

P ( at least one household ) = 0.9941

the probability that at most one household is tuned to 50 Minutes is

P ( at most one household ) = P (none)  + P (x=1)

P ( at most one household )  =0.9941 + 10C1 × (0.23)^{1} × (0.71)^{14}

P ( at most one household )  = 0.9960

and in last part If at most one household is tuned to 50 Minutes it appear that the 19% share value is not wrong

because P( at most one household ) is not zero

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