Your question is poorly formatted. However, I'm able to deduce that your question involves at least 2 algebraic fractions that needs to be simplified.

So, I'll make use of the following expression:

$\frac{3n}{n + 3} + \frac{5}{n - 4}$

When you follow the steps I'm about to provide, you'll arrive at the right answer

Required

Determine an equivalent expression

$\frac{3n}{n + 3} + \frac{5}{n - 4}$

Step 1: Take L.C.M of the denominators

$LCM = (n+3)(n-4)$

Step 2: Evaluate the fractions

$\frac{3n}{n + 3} + \frac{5}{n - 4}$ $= \frac{3n(n-4)+5(n+3)}{(n+3)(n-4)}$

Step 3: Open the brackets at the numerator

$\frac{3n}{n + 3} + \frac{5}{n - 4}$ $= \frac{3n^2-12n+5n+15}{(n+3)(n-4)}$

Step 4: Collect and evaluate like terms

$\frac{3n}{n + 3} + \frac{5}{n - 4}$ $= \frac{3n^2-7n+15}{(n+3)(n-4)}$

<em>Follow the above steps, and you'll be able to solve your question.</em>

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3 years ago