All categories

3 years ago

What is the square root of 4.84

Mathematics

2 answers:

Natasha2012 [34]3 years ago

7 0

2.2, sorry if i’m wrong

dybincka [34]3 years ago

6 0

Answer:

2.2. Hope it helps :D

You might be interested in

Help me please now I need to give it today

Hoochie [10]

9/24=3/8=0.375

42/45=14/15=0.933

84/18=14/3=4.666

6 0

3 years ago

For f(x) = 3x +1 and g(x) = x - 6, find (f- g)(x).

Finger [1]

Answer:

c. -x + 3x + 7 = 2x+7

Step-by-step explanation:

f(x) = 3x +1 and g(x) = x - 6

f-g = 3x +1 - ( x - 6)

Distribute the minus sign

= 3x+1 - x+6

= 2x +7

4 0

3 years ago

How can i differentiate this equation?

Dmitry_Shevchenko [17]

$\bf y=\cfrac{2x^2-10x}{\sqrt{x}}\implies y=\cfrac{2x^2-10x}{x^{\frac{1}{2}}} \\\\\\ \cfrac{dy}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2}x^{-\frac{1}{2}} \right)}{\left( x^{\frac{1}{2}} \right)^2}} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2\sqrt{x}} \right)}{\left( x^{\frac{1}{2}} \right)^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x}$

$\bf\cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{ \frac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2\sqrt{x}}}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2x\sqrt{x}}$

$\bf \cfrac{dy}{dx}=\cfrac{(4x-10)2x~~-~~(2x^2-10x)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~(2x^2-10x)}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~2x^2+10x}{2x\sqrt{x}} \implies \cfrac{dy}{dx}=\cfrac{6x^2-10x}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{2x(3x-5)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{3x-5}{\sqrt{x}}$

8 0

3 years ago

Help ASP!

GarryVolchara [31]

Lou has 800 pennies
Joe has 8 pennies
Therefore they have 808 pennies

3 0

3 years ago

Tell whether each relationship is a function.

Serhud [2]

Answer:

3 is a function.

1 and 2 are not.

Step-by-step explanation:

1 and 2 are not functions because we can draw a vertical line which passes through more than one point on the graphs.

You cant do this on graph 3 so it is a function.

8 0

3 years ago