1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
soldier1979 [14.2K]
3 years ago
12

Use the table to identify the phase and phase changes of the elements under the given conditions. Write the name of the substanc

e, phase, or phase change.
When the temperature in a room increases from
25°C to 33°C,
______ changes from a solid
to a liquid.
In a lab, methane and nitrogen are cooled from
-170°C to -200°C. The methane freezes and the
nitrogen _____
.
When gold is heated to 2,856°C it changes from a liquid to a ____

Chemistry
2 answers:
saul85 [17]3 years ago
4 0

See attached picture of the right responses to the phase change question.

OLga [1]3 years ago
3 0

<u>Answers:</u>

1. When the temperature in a room increases from25°C to 33°C, <u>galium</u> changes from a solid to a liquid.

2. In a lab, methane and nitrogen are cooled from -170°C to -200°C. The methane freezes and the nitrogen <u>condenses</u>.

3. When gold is heated to 2,856°C it changes from a liquid to a <u>gas</u>

<u>Explanations</u>:

The melting and boiling point of the substances permit to state whether a susbstance will be solid, liquid or gas at certain conditions (temperature in this case).

Melting point: is the temperature at which a solid becomes liquid.

Boiling point is the temperature at which a liquid becomes gas.

Hence:

  • if the temperature is below the melting point, the substance is solid.
  • if the temperature is between the melting and the boiling points, the substance is liquid.
  • if the emperature is above the boiling point the substance is gas.

The names of the phase changes dealt with in this question are:

  • Condenstation: pass from gas to liquid.
  • Boiling (Vaporization): pass from liquid to gas
  • Freezing: pass from liquid to solid.
  • Melting (fusion): pass from solid to liquid

With that let us go through the three statements:

<em>1. When the temperature in a room increases from25°C to 33°C,</em>

<em>______ changes from a solid to a liquid. </em>Answer: galium.

You need to find in the table a substance whose melting point is between 25°C and 33°C.

This is Gallium, whose melting point is indicated to be 30°C, meaning that at 25°C it is solid and at 33°C it is liquid.

<em>2. In a lab, methane and nitrogen are cooled from -170°C to -200°C. The methane freezes and the nitrogen _____</em>. Answer: condenses.

Since the boling point of nitrogen is - 196°C, at  -170°C nitrogen is gas.

Since, the melting point is - 210°C, at -200°C, nitrogen is liquid.

So, nitrogen condenses when it is cooled from - 170°C to - 200°C.

<em>3. When gold is heated to 2,856°C it changes from a liquid to a ____. </em>Answer: gas.

Since, 2856°C is the boiling point of gold, it will start fo pass from liquid to gas at this temperature.

You might be interested in
Does Helium Have Chemical Properties? Helium doesn't react with other substances. Is it still accurate to say that helium has no
Greeley [361]
No, it is not accurate: Chemical properties of helium - Health effects ofhelium. Gaseous chemical element, symbol: He, atomic number: 2 and atomic weight 4,0026 g/mol. Helium is one of the noble gases of group O in the periodic table.
7 0
3 years ago
A 1.50 liter flask at a temperature of 25°C contains a mixture of 0.158 moles of methane, 0.09 moles of ethane, and 0.044 moles
RUDIKE [14]
This can be solved using Dalton's Law of Partial pressures. This law states that the total pressure exerted by a gas mixture is equal to the sum of the partial pressure of each gas in the mixture as if it exist alone in a container. In order to solve, we need the partial pressures of the gases given. Calculations are as follows:

P = P1 + P2 + P3
P = (82.0575 atm.cm^3/mol.K)( 298.15 K)/1.50 x 10^3 cm^3) x (<span>0.158 mole + 0.09 mol + 0.044 mol) = 4.76 atm</span>
3 0
4 years ago
5.36 liters of nitrogen gas are at STP. What would be the new volume if we increased the moles from 3.5 moles to 6.0 moles?
Aleksandr [31]

Answer:

V_2=9.20L

Explanation:

Hello there!

In this case, according to the given STP (standard pressure and temperature), it is possible for us to realize that the equation to use here is the Avogadro's law as a directly proportional relationship between moles and volume:

\frac{V_2}{n_2}= \frac{V_1}{n_1}

In such a way, given the initial volume and both initial and final moles, we can easily compute the final volume as shown below:

V_2= \frac{V_1n_2}{n_1} \\\\V_2=\frac{5.36L*6.0mol}{3.5mol}\\\\V_2=9.20L

Best regards!

3 0
3 years ago
In the laboratory a student determines the specific heat of a metal. He heats 19.5 grams of copper to 98.27 °C and then drops it
siniylev [52]

Answer:

The specific heat of copper is 0.37 J/g°C

Explanation:

<u>Step 1: </u>Data given

Mass of copper = 19.5 grams

Initial temperature of copper = 98.27 °C

Mass of water = 76.3 grams

Initial temperature of water = 24.05 °C

Final temperature of water and copper = 25.69 °C

<u>Step 2:</u> Calculate specific heat of copper

Qgained = -Qlost

Q = m*c*ΔT

Qwater = -Qcopper

m(water) * c(water) * ΔT(water) = - m(copper) * c(copper) *ΔT(copper)

⇒ with m(water) = 76.3 grams

⇒ with c(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2-T1 = 25.69 - 24.05 = 1.64

⇒ with m(copper) = 19.5 grams

⇒ with c(copper) = TO BE DETERMINED

⇒ with ΔT(copper) = T2-T1 = 25.69 - 98.27 = -72.58

76.3 * 4.184 * 1.64 = - 19.5 * c(copper) * -72.58

523.552 = 1415.31 * c(copper)

c(copper) = 0.37 J/g°C

The specific heat of copper is 0.37 J/g°C

3 0
4 years ago
How many grams of gasoline would you need to burn to move your car 2.5 miles which takes 5,375 kJ? (Hrxn= 47kJ/g)
docker41 [41]

Answer:

1.1 × 10² g

Explanation:

The combustion of gasoline releases energy that is used to move the car. The enthalpy of reaction (ΔH°rxn) of the combustion of gasoline is 47 kJ/g, that is, 47 kiloJoule are produced per gram of gasoline burned. The mass of gasoline to be burned to release 5,375 kJ is:

5,375 kJ × 1 g Gasoline/47 kJ = 1.1 × 10² g

4 0
3 years ago
Other questions:
  • Classify each of these reactions.
    7·1 answer
  • Explain why your hair might stand up when going down a slide.
    8·2 answers
  • Find the mass in 2.6 mol of lithium bromide
    13·2 answers
  • How do the forces affect men
    7·1 answer
  • WILL MARK BRAINLIEST
    6·1 answer
  • The continued use of fertilizer can cause change in the pH of the growing medium. Which of the following materials will make the
    9·1 answer
  • 4. Escribe una apreciación crítica acerca de la conservación de alimentos mediante el uso del ÁCIDO SULFHÍDRICO
    6·1 answer
  • Las Vegas, Nevada is in a desert. How does its rapid population growth affect the
    9·1 answer
  • Which environment has lower temperatures at higher elevations?
    12·2 answers
  • This circuit shows a battery and wires connected to a lightbulb. The chemical energy in the battery is converted to:
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!