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3 years ago

How do you turn 53 1/3 into a fraction????

Mathematics

2 answers:

goldfiish [28.3K]3 years ago

7 0

160/3 is 53 1/3 as a fraction

spin [16.1K]3 years ago

4 0

That would be an improper fraction.

Multiply denominator by the whole number and add the whole number to the numerator. Remember that you don't have to change the denominator. The new number will be your numerator

Whole number = 53
Numerator = 1
Denominator = 3

Denominator × Whole number + Numerator

3 × 53 + 1 = 160 and the denominator is 3 as it was in the mixed fraction

$53 \frac{1}{3} = \frac{160}{3}$

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Solve for w. 7(-2w + 3) = 1 - 4w <br>what is the value of w?

blondinia [14]

Answer:

w=2

Step-by-step explanation:

-14w + 21 = 1 - 4w

-10w + 21 = 1

-10w = -20

w = -20/-10

w=2

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2 years ago

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camilla paid $1.15 per pound for x pounds of tomatoes. She paid for her tomatoes with $10 and received $4.48 in change. How many

Alika [10]

Answer:

$x=4.8\ pounds$

Step-by-step explanation:

Let

x-----> the number of pounds of tomatoes Camilla bought

we know that

The equation that represent this situation is equal to

$1.15x=10-4.48$

Solve for x

$1.15x=5.52$

$x=5.52/1.15$

$x=4.8\ pounds$

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3 years ago

PLEASE HELP ASAP ILL GIVE BRAINLIEST

Veseljchak [2.6K]

Answer:

x>-23/7

Step-by-step explanation:

-23<7x

7x>-23

x>-23/7

the answer is x>-23/7

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2 years ago

Michela’s skateboard ramp is at an incline of 40°. When she attempts a trick on the ramp, she finds that it is too steep. She ad

marissa [1.9K]

Answer:

22.7604763 degrees

Step-by-step explanation:

Note that the answer is NOT 20 degrees.

She adjusted the ramp to half the original <em>incline</em>

Therefore we have tan 40 = x = 0.839099631.

We want an incline of y degrees where tan y = x/2 = 0.839099631/2 = 0.419549815

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2 years ago

Every day your friend commutes to school on the subway at 9 AM. If the subway is on time, she will stop for a $3 coffee on the w

Shtirlitz [24]

Answer:

1.02% probability of spending 0 dollars on coffee over the course of a five day week

7.68% probability of spending 3 dollars on coffee over the course of a five day week

23.04% probability of spending 6 dollars on coffee over the course of a five day week

34.56% probability of spending 9 dollars on coffee over the course of a five day week

25.92% probability of spending 12 dollars on coffee over the course of a five day week

7.78% probability of spending 12 dollars on coffee over the course of a five day week

Step-by-step explanation:

For each day, there are only two possible outcomes. Either the subway is on time, or it is not. Each day, the probability of the train being on time is independent from other days. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem we have that:

The probability that the subway is delayed is 40%. 100-40 = 60% of the train being on time, so $p = 0.6$

The week has 5 days, so $n = 5$

She spends 3 dollars on coffee each day the train is on time.

Probabability that she spends 0 dollars on coffee:

This is the probability of the train being late all 5 days, so it is P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{5,0}.(0.6)^{0}.(0.4)^{5} = 0.0102$

1.02% probability of spending 0 dollars on coffee over the course of a five day week

Probabability that she spends 3 dollars on coffee:

This is the probability of the train being late for 4 days and on time for 1, so it is P(X = 1).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 1) = C_{5,1}.(0.6)^{1}.(0.4)^{4} = 0.0768$

7.68% probability of spending 3 dollars on coffee over the course of a five day week

Probabability that she spends 6 dollars on coffee:

This is the probability of the train being late for 3 days and on time for 2, so it is P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{5,2}.(0.6)^{2}.(0.4)^{3} = 0.2304$

23.04% probability of spending 6 dollars on coffee over the course of a five day week

Probabability that she spends 9 dollars on coffee:

This is the probability of the train being late for 2 days and on time for 3, so it is P(X = 3).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{5,3}.(0.6)^{3}.(0.4)^{2} = 0.3456$

34.56% probability of spending 9 dollars on coffee over the course of a five day week

Probabability that she spends 12 dollars on coffee:

This is the probability of the train being late for 1 day and on time for 4, so it is P(X = 4).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 4) = C_{5,4}.(0.6)^{4}.(0.4)^{1} = 0.2592$

25.92% probability of spending 12 dollars on coffee over the course of a five day week

Probabability that she spends 15 dollars on coffee:

Probability that the subway is on time all days of the week, so $P(X = 5)$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 5) = C_{5,5}.(0.6)^{5}.(0.4)^{0} = 0.0778$

7.78% probability of spending 12 dollars on coffee over the course of a five day week

8 0

3 years ago