Answer:
Step-by-step explanation:
add a picture of the question please
Step-by-step explanation:
Y= x - 2. Y = 3x + 5
Putting value of y
x - 2 = 3x + 5
-2 - 5 = 3x - x
-7 = 2x
-7/2 = x
Putting value of x
Y = 3(-7/2) + 5
Y = - 10.5 + 5
Y = - 5.5
The answer is a.0.32 km.
The speed that a tsunami can travel is modeled by the equation is s = 356√d.
It is given:
s = 200 km/h
d = ?
Now, let's substitute s in the equation and find d:
s = 356√d
200 = 356√d
√d = 200 ÷ 356
√d = 0.562
Now, let's square both sides of the equation:
(√d)² = (0.562)²
d = (0.562)² = 0.316 ≈ 0.32
Therefore, <span> the approximate depth (d) of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.</span>
Answer: 300*0.73^x
Step-by-step explanation:
300 is the initial value and every time x goes up by 1, the value get multiplied by 0.73
when x=3
then the value would be 300*0.73*0.73*0.73 or 300*0.73^3
then for x amount of times the equation would be 300*(0.73 x times ) or 300*0.73^x
