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3 years ago

I am in a sticky situation here I am not sure what the answer is

Mathematics

2 answers:

DedPeter [7]3 years ago

4 0

Answer:

The selected in answer is correct, I believe.

Step-by-step explanation:

GarryVolchara [31]3 years ago

3 0

Answer: I would go with 66ft

Hope this helps!!! Good luck!!! ;)

You might be interested in

There are only red, blue and green counters in a bag.

emmainna [20.7K]

Answer:

A 4/10

B 5/10

Step-by-step explanation:

A because there are 4 out of the 10 that are red

B because there 5 out of the 10 that are not blue

6 0

3 years ago

The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s

Norma-Jean [14]

The positions when the particle reverses direction are:

$s(t_1)=55ft\\\\s(t_2)=28ft$

The acceleraton of the paticle when reverses direction is:

$a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}$

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

$s(t)=2t^{3}-21t^{2}+60t+3$

So,

- Derivating to get the velocity function, we have:

$v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60$

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

$v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s$

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

$a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42$

Now, substituting the times to calculate the accelerations, we have:

$a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}$

Now, substitutitng the times to calculate the positions, we have:

$s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft$

Have a nice day!

3 0

3 years ago

Angel works in a dentist’s office making $13.50 an hour. She works 40 hours per week. How much does she make in a year?

-Dominant- [34]

This is a 2 part question, so we will go step by step

Since Angel makes 13.50 an hour, and she works 40 hours a week, we have to make an equation and solve it.

First, let's make the equation, and we should multiply. Why?

Because finding out how much she made in a week would make it easier to find out how much she makes in a year. To find out how much she makes in a week, we need to add 13.50 40 times, and multiplication is an easier way of doing that.

Now to set it up, 40 is the number we are multiplying by (Because 40 is how many hours she works, and 13.50 is how much she makes in that hour)

and 13.50 is the number getting multiplied

Now we insert numbers into typical multiplication format

13.50 x 40 = ?

Now we solve

13.50 x 40 = 540

So she makes 540 dollars in a week, now we need to multiply that by the number of weeks they are in a year and we are done.

With a little help from Google, we can learn that there are in 52.1 weeks in a common year.

Now we do the same thing we did the last time and insert our numbers into the equation.

(52.1 is what we are multiplying by, and 540 is the number that is getting multiplied.)

540 x 52.1 = ?

Solve

540 x 52.1 = 28,134

She makes 28,134 in a year

Hope this helped!

3 0

3 years ago

Which equation is equivalent to 4s=t+2

Paraphin [41]

Answer:If we're solving for t my work is below:

t = 4 s - 2

If we're solving for s my work is below:

s = t + 2/4

Step-by-step explanation:

7 0

3 years ago

What is the value of the 10th term in this arithmetic sequence? 2,5,8,11,...

yKpoI14uk [10]

It looks to be 29, if the rule is to add 3z

8 0

3 years ago