The horizontal distance between light house and boat is 1588.78 feet approximately.
The figure is given by,
Here, AB = height of the lighthouse bacon light above the water = 139 feet
Now angle ACB = 5 degree
Let the horizontal distance of light house from the boat = BC = x feet
So by trigonometric function we get,
tan 5 = AB/BC
tan 5 = 139/x
x = 139/tan 5 = 1588.78 (approximately)
Hence the horizontal distance between light house and boat is 1588.78 feet approximately.
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Answer:
n-58
Step-by-step explanation:
Answer:
• x = 9
• y = 6√2
Step-by-step explanation:
The right triangles are all similar, so the ratios of hypotenuse to short side are the same:
27/x = x/3
x^2 = 81 . . . . . multiply by 3x
x = 9 . . . . . . . . take the square root
Then y can be found from the Pythagorean theorem:
x^2 = y^2 + 3^2
81 - 9 = y^2 = 72 . . . . . subtract 9
y = √72 = 6√2 . . . . . . .take the square root
The values of x and y are 9 and 6√2, respectively.
I think the answer is 816cm