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2 years ago

What is the answer to this

Mathematics

1 answer:

patriot [66]2 years ago

6 0

Answer:

The domain and range are both x > -4

Step-by-step explanation:

hope it helps have a great day

<em>plz mark brainlest!!</em>

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How to put 1760 into a fraction

Nikolay [14]

Is there a decimal, if so i can answer.

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2 years ago

Read 2 more answers

The shaded region in the graph represents the solutions of this system of linear inequalities:

kotegsom [21]

Answer:

$y$

$y\leq 2x+3$

Step-by-step explanation:

step 1

Find the equation of the solid line

From the graph take the points (0,3) and (4,11)

Find the slope

$m=(11-3)/(4-0)\\m=8/4=2$

The equation of the solid line in slope intercept form is equal to

$y=mx+b$

we have

$m=2$

$b=3$ ----> the y-intercept is the point (0,3)

substitute

$y=2x+3$

therefore

The inequality is

$y\leq 2x+3$

step 2

Find the equation of the dashed line

The slope is given

$m=4$

From the graph take the y-intercept (0,-5)

The equation of the solid line in slope intercept form is equal to

$y=mx+b$

we have

$m=4$

$b=-5$

substitute

$y=4x-5$

therefore

The inequality is

$y$

because the shaded region is below the dashed line

therefore

The system of inequalities is

$y$

$y\leq 2x+3$

8 0

2 years ago

Did I do this right? (Accounting)

levacccp [35]

Yes you did, congratulations ;-)

4 0

2 years ago

PLEASE HELP ME!!! Thank you SO MUCH! Explain your answer

soldi70 [24.7K]

Answer:

y = -.5x -.5

Step-by-step explanation:

All you do is plug in the x and y in the point to the equation, y = mx + b. Since the coordinate is (5, -3), this in the equation would look like -3 = -.5(5) +b. (all you need to find is the y-intercept, or b.) Solve it out to get -3 = -2.5 + b. Add 2.5 to each side of the equation, you're left with b = -.5. Now, put that back into the original equation, and get y = -.5x -.5. I think this is right, you can go back through and check once more if you'd like.

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3 years ago

What is the midpoint of a segment with These endpoints (-6,-9) and (16,5)

lora16 [44]

$~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{-9})\qquad (\stackrel{x_2}{16}~,~\stackrel{y_2}{5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 16 -6}{2}~~~ ,~~~ \cfrac{ 5 -9}{2} \right)\implies \left( \cfrac{10}{2}~~,~~\cfrac{-4}{2} \right)\implies (5~~,~-2)$

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2 years ago