The sum of the square of two consecutive odd intergers is 290. Find the integers.

Mathematics

1 answer:

hoa [83]3 years ago

5 0

Answer:

11 & 13 or - 13 & - 11

Step-by-step explanation:

Let the integers are a - 1 and a + 1.

Sum of squares = 290

=> (a - 1)² + (a + 1)² = 290

=> a² + 1² - 2a + a² + 1² + 2a = 290

=> 2a² + 2 = 290

=> 2(a² + 1) = 290

=> a² + 1 = 290/2 = 145

=> a² = 145 - 1 = 144

=> a = ± √144 = ± 12

If a = + 12, numbers are

12 - 1 = 11 & 12 + 1 = 13

If a = - 12, numbers are

- 12- 1 = - 13 & - 12 + 1 = - 11

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