The sum
of the square of two consecutive
odd intergers is
290. Find the integers.
1 answer:
Answer:
11 & 13 or - 13 & - 11
Step-by-step explanation:
Let the integers are a - 1 and a + 1.
Sum of squares = 290
=> (a - 1)² + (a + 1)² = 290
=> a² + 1² - 2a + a² + 1² + 2a = 290
=> 2a² + 2 = 290
=> 2(a² + 1) = 290
=> a² + 1 = 290/2 = 145
=> a² = 145 - 1 = 144
=> a = ± √144 = ± 12
If a = + 12, numbers are
12 - 1 = 11 & 12 + 1 = 13
If a = - 12, numbers are
- 12- 1 = - 13 & - 12 + 1 = - 11
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