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denis-greek [22]
3 years ago
14

Help plz math !!!!!

Mathematics
1 answer:
kramer3 years ago
3 0

Answer:

Perimeter of the windows is P = 4s, or (here) P = 4(x+9) ft.

Step-by-step explanation:

If the area of the square is x^2 + 18x + 81 (ft^2), then the length of one side is given by the square root of that, and is x + 9 (ft). Note that (x + 9)^2 = x^2 + 18x + 81.

The perimeter of a square window of side length s is P = 4s.

Here, the perimeter of the square is P = 4(x+9) (ft).

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2 classes have a total of 50 students. One of the classes has 6 more students than the other. How many students are in the large
iogann1982 [59]
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7 0
3 years ago
According to the February 2008 Federal Trade Commission report on consumer fraud and identity theft, 23% of all complaints in 20
Murljashka [212]

Answer:

There is not enough evidence to support the claim that Alaska had a lower proportion of identity theft than 23%.  

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 1432

p = 23% = 0.23

Alpha, α = 0.05

Number of theft complaints , x = 321

First, we design the null and the alternate hypothesis  

H_{0}: p = 0.23\\H_A: p < 0.23

This is a one-tailed test.  

Formula:

\hat{p} = \dfrac{x}{n} = \dfrac{321}{1432} =0.2241

z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}

Putting the values, we get,

z = \displaystyle\frac{0.2241-0.23}{\sqrt{\frac{0.23(1-0.23)}{1432}}} = -0.5305

Now, we calculate the p-value from the table.

P-value = 0.298

Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept the null hypothesis.

Conclusion:

Thus, there is not enough evidence to support the claim that Alaska had a lower proportion of identity theft than 23%.

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