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4 years ago

6

Solve the following for the x and y values. X being 0 when solving for Y, and vice versa.

1 answer:

Aleonysh [2.5K]4 years ago

3 0

It states your "X" will be zero when solving for "Y". So when solving for "Y" your equation would be; 0+y=4 Then you solve. Y=4 Then you do the same with the "X": X+0=4. Then you solve. X=4 It would end up being (4(x),4(y) ) Then do the same for the next problem.

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What is the prime factorization of 189

Karo-lina-s [1.5K]

189 : 3 = 63

63 : 3 = 21

21 : 3 = 7

7 : 7 = 1

<h3>189 = 3 · 3 · 3 · 7 = 3³ · 7</h3>

4 0

3 years ago

Read 2 more answers

(f-g)(x) <br> f(x)= 1/x+2 <br> g(x)= 3x

prohojiy [21]

Answer:

f(x) - g(x) = (1/x) + 2 - 3x or (f - g)(x)

Step-by-step explanation:

f(x) = 1/x+2

-g(x) = 3x

can be summarized on line line as:

f(x) - g(x) = (1/x) + 2 - 3x or (f - g)(x)

7 0

4 years ago

Find the distance between the points (a, 0) and (0, b). StartRoot (a minus b) squared EndRoot StartRoot a squared + b squared En

rewona [7]

Answer:

$\sqrt{a^2+b^2}$

Step-by-step explanation:

Calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = (a, 0) and (x₂, y₂ ) = (0, b)

d = $\sqrt{(0-a)^2+(b-0)^2}$

= $\sqrt{(-a)^2+b^2}$

= $\sqrt{a^2+b^2}$

5 0

4 years ago

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7d – 8 = 3d + 8 help me

Mice21 [21]

Answer:

Step-by-step explanation:

7d – 8 = 3d + 8

7d - 3d = 8 + 8

4d = 16

d = 16 /4

d = 4

4 0

3 years ago

Please help this is so confusing

riadik2000 [5.3K]

The answer is 24

You want to replace the x in the expression x^2-2x with 6
36-12
24
Hope this helps

5 0

2 years ago

Read 2 more answers