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Marina86 [1]
3 years ago
10

PLEAASE HELPPP whoever solves this will mark brainliest

Mathematics
1 answer:
weqwewe [10]3 years ago
6 0

Answer:

12

Step-by-step explanation:

Perimeter of ΔABC = 12+ perimeter of ΔACD

Perimeter of ΔABC= AC+CB+BA

Perimeter of ΔACD=AC+CD+DA

But, CB=CD +DB

DA ≅DB since there is a ⊥bisector trough D and

Therefore,

Perimeter of ΔABC= (AC+CD+DA)+BA = Perimeter of ΔACD +12 therefore AB=12

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What equation is parallel to y= -1/4+5 and passes through (2,-3)? <br> HELPPPPP PLEASE!!!!
IrinaVladis [17]

Answer:

y = -1/4x - 5/2.

Step-by-step explanation:

I am assuming you mean y = -1/4x + 5.

This has slope of -1/4 so the required equation has the same slope ( as they are parallel).

Using the point-slope form of the equation of a line:

y - (-3) = -1/4(x - 2)

y + 3 = -1/4(x - 2)

y = -1/4x + 1/2 - 3

y = -1/4x - 5/2

5 0
3 years ago
The box plots below show student grades on the most recent exam compared to overall grades in the class
DaniilM [7]

Answer:

3. The class median is lower than the exam median

Step-by-step explanation:

The median of the box plot is indicated by the vertical line that divides the box.

Thus, the Class median grade is about 80, while the Exam median grade is more than 80.

Comparing grades, this means that the class median is lower. than the exam median.

Therefore, "the class median is lower than the exam median" is the right information that describes the median.

5 0
3 years ago
Solve the equation 3+<br> х<br> * = 10.<br> X=
garik1379 [7]
If the equation is 3+x=10, x is equal to 7
5 0
3 years ago
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Sarah need 7 tickets, how much does it cost if 9 tickets cost 159 dollars
natulia [17]

Answer:

I think it's $123

Step-by-step explanation:

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3 0
3 years ago
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What is an equation of the line that passes through the point (−6,−1) and is perpendicular to the line 6x−y=7?
user100 [1]

Answer:

y=-1/6x-2

Step-by-step explanation:

Lets find the slope of the given line

6x-7=y,m=6

The slope of the perpendicular line would be=-1/6

Using the point-slope form y-y1=m(x-x1)

y--1=-1/6(x--6)

y+1=-1/6(x+6)

6y+6=-x-6

6y=-x-6-6

6y=-x-12

y=-1/6x-2

6 0
3 years ago
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