PLEAASE HELPPP whoever solves this will mark brainliest
1 answer:
Answer:
12
Step-by-step explanation:
Perimeter of ΔABC = 12+ perimeter of ΔACD
Perimeter of ΔABC= AC+CB+BA
Perimeter of ΔACD=AC+CD+DA
But, CB=CD +DB
DA ≅DB since there is a ⊥bisector trough D and
Therefore,
Perimeter of ΔABC= (AC+CD+DA)+BA = Perimeter of ΔACD +12 therefore AB=12
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4 (x-3)=3x-4
4x-12=3x-4
4x-12-3x=3x-4-3x
x-12=-4
x-12+12=-4+12
x=8
What do you mean by version
SOHCAHTOA
A = 4/3
H = sqrt 3
O = -sqrt 11
sin is O/H so:
sin = -sqrt 11 / sqrt 3
Find the area of all the sides:
10 x 9 = 90
9 x 8 = 72
1/2 x 6 x 8 = 24
1/2 x 6 x 8 = 24
6 x 9 = 54
Add them up:
90 + 72 + 24 + 24 + 54 = 264 square metres
