Question

8 points! Please help me with this problem, what is sin(theta)?

Answer 1

sin=√17/7

or sin=sqrt(17)/7

Answer 2

Answer:

$\frac{\sqrt{17} }{7}$

Step-by-step explanation:

Given

cosΘ = $\frac{4\sqrt{2} }{7}$ = $\frac{adjacent}{hypotenuse}$

Then the hypotenuse of the right triangle is 7 and the adjacent side is 4$\sqrt{2}$

To find the opposite side use Pythagoras' identity

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

opp² + (4$\sqrt{2}$ )² = 7²

opp² + 32 = 49 ( subtract 32 from both sides )

opp² = 17 ( take the square root of both sides )

opp = $\sqrt{17}$

Hence

sinΘ = $\frac{opposite}{hypotenuse}$ = $\frac{\sqrt{17} }{7}$