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miss Akunina [59]
3 years ago
10

Please help asap!!!look at the box

Mathematics
2 answers:
exis [7]3 years ago
5 0
I think it’s B might be wrong though
Nina [5.8K]3 years ago
5 0

Answer:

y

Step-by-step explanation:

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What is 5/10 times 2/4 show step by step explanation HELP ASAP
Darya [45]

5/10 *2/4

Cross out 2 and 10, divide by 2. 2/2=1 , 10/2=5

5/5*1/4= 5/20

reduce the fraction

divide by 5 for the numerator and denominator

5/5=1

20/5=4

5/10*2/4=1/4

Answer: 1/4

5 0
3 years ago
I need help, please!! I'll give a brainliest
kvasek [131]

Answer:

metals or metalloids

Step-by-step explanation:

I'm built different i dont know if im right about the question. im just not sure if i understood the question correctly

3 0
3 years ago
I need help on 11-16
alisha [4.7K]
I cant see all of 11 and 14
12:
3f = 18 \\   \frac{3f}{3}  =  \frac{18}{3}  \\ f = 6
13:
3f =  {3}^{2}  \\ 3f = 9 \\  \frac{3f}{3}  =  \frac{9}{3}  \\ f = 3
15:
3h = 9 + 10 \\ 3h = 19 \\  \frac{3h}{3}  =  \frac{19}{3}  \\ h = 6.3
16:
3f = 27 - 21 \\ 3f = 6 \\  \frac{3f}{3}  =  \frac{6}{3}   \\ f = 2
6 0
4 years ago
write the equation in slope-intercept form of the line passing through the points (-3, -2) and (-5, 2) hint: y = mx + b, all wor
Mama L [17]

Answer:

y(x) = -2x -8

Step-by-step explanation:

using the hint, insert the points (x,y) in the equation:

-2 = -3m + b       eq1

2 = -5m + b        eq2

eq2 - eq1 :  

4 = -2m  ==> m = -2

insert m in eq1:    

-2 = -3*(-2) +b   ==> b = -8

4 0
3 years ago
I built a storage shed in the shape of a rectangular box on a square base. The material that I used for the base cost $4 per squ
kumpel [21]

Answer:

side of 6.124 ft and height of 3.674 ft

Step-by-step explanation:

Let's s be the side of the square base and h be the height of the rectangular box.

The base and the roof would have an area of s^2 and cost of

4s^2 + 2s^2 = 6s^2

The sides would have an area of 4sh and cost of 4sh*2.5 = 10sh

So the total cost for the material is

6s^2 + 10sh = 450

10sh = 450 - 6s^2

h = 45/s - 0.6s

The volume of the shed has the following formula

V = s^2h = s^2(45/s - 0.6s) = 45s - 0.6s^3

To find the maximum value for V, we can take its first derivative, and set it to 0

\frac{dV}{ds} = 45 - 1.2s^2 = 0

1.2s^2 = 45

s^2 = 45 / 1.2 = 37.5

s = \sqrt{37.5} = 6.124 ft

h = 45/s - 0.6s = 3.674 ft

4 0
3 years ago
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