1.
write 1 as
![log_{4}4](https://tex.z-dn.net/?f=log_%7B4%7D4)
so that we compare same base logarithms:
![log_{4}[{ log_{4}}2x]= log_{4}4](https://tex.z-dn.net/?f=%20log_%7B4%7D%5B%7B%20log_%7B4%7D%7D2x%5D%3D%20%20log_%7B4%7D4)
2. Neglect the equal bases and write the arguments:
So
![{ log_{4}}2x=4](https://tex.z-dn.net/?f=%7B%20log_%7B4%7D%7D2x%3D4)
repeat step 1, that is write 4 as a logarithm with base 4:
![4=4*1=4* log_{4}4= log_{4} 4^{4}](https://tex.z-dn.net/?f=4%3D4%2A1%3D4%2A%20log_%7B4%7D4%3D%20log_%7B4%7D%204%5E%7B4%7D%20)
3.
Answer:
D. 5x^2 + 2y^2 + 12x + 5y
Step-by-step explanation:
6x + 2y + y^2 + 6x + 2y + y^2 + 4x^2 + x^2 + y
6x + 6x = 12x
12x + 2y + y^2 + 2y + y^2 + 4x^2 + x^2 + y
2y + 2y + y = 5y
12x + 5y + y^2 + y^2 + 4x^2 + x^2
y^2 + y^2 = 2y^2
2y^2 + 4x^2 + x^2 + 12x + 5y
4x^2 + x^2 = 5x^2
2y^2 + 5x^2 + 12x + 5y
5x^2 + 2y^2 + 12x + 5y