Find the lateral area of the cone in terms of pi. Radius 3cm, height 4
1 answer:
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Answer: The answers is (B) equal areas.
Step-by-step explanation: Given that two triangles have equal perimeters.
As shown in the attached figure, let us consider two right-angles triangles, ΔABC and ΔDEF, with sides AB = 3 cm, BC = 4 cm, AC = 5 cm, DE = 4 cm, EF = 3 cm and DF = 5 cm.
So the perimeters of both the triangles = 3 + 4 + 5 = 4 + 3 + 5 = 12 cm.
Since volume term is not valid in case of triangles, so they cannot have equal volumes. Therefore, option (A) is incorrect.
Area of ΔABC is
and area of ΔDEF is
Therefore, they may have equal areas and so option (B) is correct.
If the triangles have equal bases, then the heights will also be equal and both the triangles will be same. Similar is the case with equal heights. So, options (C) and (D) are incorrect.
Thus, the correct option is (B). equal areas.
He drank more than half of his drink... So we need to look for fractions greater than 1/2.
First, lets find equivalents of 1/2
If all of these fractions are equal to 1/2, then by adding to the numerator of these fractions, we'l have fractions greater than 1/2.
2 +1 3
__= ___
4 4
3/4 is greater than 1/2
Mike could have drunken 3/4 of the juice
4/6>1/2 Mike could have drunken 4/6 of the juice
5/8 is greater then 1/2 Mike could have drank 5/8 of the drink.
Answer=3/4, 4/6, 5/8 and many more possible fractions
First, lets find equivalents of 1/2
If all of these fractions are equal to 1/2, then by adding to the numerator of these fractions, we'l have fractions greater than 1/2.
2 +1 3
__= ___
4 4
3/4 is greater than 1/2
Mike could have drunken 3/4 of the juice
4/6>1/2 Mike could have drunken 4/6 of the juice
5/8 is greater then 1/2 Mike could have drank 5/8 of the drink.
Answer=3/4, 4/6, 5/8 and many more possible fractions