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Stels [109]
3 years ago
14

I screenshot the question.

Mathematics
1 answer:
Alexxx [7]3 years ago
6 0

Answer:

17     34

24    58

31     89

38    127

45    172

52    224

59    283

62    345

69    414

76    490

83    573

Step-by-step explanation:

Filling up the chart, you will get 227 at the 15 score mark. (You can just continuously add)

Then at the final answer you add the results to total pushups you get 573.

There is a faster way to do this using a formula, but probably will go over your head.

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draw3 rows with 2 counters in each row write a word problem that can be acted out using these counters
Gnoma [55]
Pretend * is counter

*   *   *
*   *   *

the word problem could be in a box of chocolates there is 3 rows and 2 chocolates in each row how many chocolates are there total.
6 0
3 years ago
Read 2 more answers
Evaluate. Can someone please help me on this?
bagirrra123 [75]
= 12 x (4^2)
= 12 x 16
= 192
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4 years ago
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(-2 1/3 + 5 1/5) + 1 1/3 =
Iteru [2.4K]

4Answer:

exact form:

\frac{21}{5\\}

decimal form:

4.2

mixed number form:

4\frac{1}{5}

Step-by-step explanation:

6 0
3 years ago
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Find a linear approximation of the function f(x)=\sqrt[3]{1+x} at a=0, and use it to approximate the numbers \sqrt[3]{.96} and \
34kurt
f(x)=\sqrt[3]{1+x}=(1+x)^{1/3}\implies f'(x)=\dfrac1{3(1+x)^{2/3}}

The linear approximation to f(x) around x=a is then

L(x)=f(a)+f'(a)(x-a)\approx f(x)

So the approximation centered at a=0 will be

L(x)=f(0)+f'(0)x=(1+0)^{1/3}+\dfrac x{3(1+0)^{2/3}}
L(x)=1+\dfrac x3

which means we have

\sqrt[3]{0.96}\approx L(0.96)=1+\dfrac{0.96}3=1.32

\sqrt[3]{1.02}\approx L(1.02)=1+\dfrac{1.02}3=1.34

Compare to the actual values of

\sqrt[3]{0.96}\approx0.9864

\sqrt[3]{1.02}\approx1.0066
4 0
3 years ago
The john boy peanut company produces 145 pound of peanut in day each yard they fill holds 18 ounces of peanut . Each crate they
xeze [42]
145 pounds = 2,320 ounces
2,320 ÷ 18 = 128 jars and some left over in one day
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