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3 years ago

PLEASE HELP

Mathematics

2 answers:

Nana76 [90]3 years ago

5 0

Answer = addition and multiplication

Goryan [66]3 years ago

4 0

Answer:

A. and C. Hope it helped brainiest plz

Step-by-step explanation:

Answer would be :

The set of whole numbers is closed by C. and A.

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Please help! I don't understand!

Vinvika [58]

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3 years ago

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Simplify the expression 6h +(-7.1d) – 17 + 4d – 2.4h

Alexxx [7]

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11.1d + 3.2h - 15

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Evaluate the line integral, where c is the given curve. (x + 9y) dx + x2 dy, c c consists of line segments from (0, 0) to (9, 1)

viktelen [127]

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=\int_C\langle x+9y,x^2\rangle\cdot\underbrace{\langle\mathrm dx,\mathrm dy\rangle}_{\mathrm d\mathbf r}$

The first line segment can be parameterized by $\mathbf r_1(t)=\langle0,0\rangle(1-t)+\langle9,1\rangle t=\langle9t,t\rangle$ with $0\le t\le1$ . Denote this first segment by $C_1$ . Then

$\displaystyle\int_{C_1}\langle x+9y,x^2\rangle\cdot\mathbf dr_1=\int_{t=0}^{t=1}\langle9t+9t,81t^2\rangle\cdot\langle9,1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(162t+81t^2)\,\mathrm dt$
$=108$

The second line segment ( $C_2$ ) can be described by $\mathbf r_2(t)=\langle9,1\rangle(1-t)+\langle10,0\rangle t=\langle9+t,1-t\rangle$ , again with $0\le t\le1$ . Then

$\displaystyle\int_{C_2}\langle x+9y,x^2\rangle\cdot\mathrm d\mathbf r_2=\int_{t=0}^{t=1}\langle9+t+9-9t,(9+t)^2\rangle\cdot\langle1,-1\rangle\,\mathrm dt$
$=\displaystyle\int_0^1(18-8t-(9+t)^2)\,\mathrm dt$
$=-\dfrac{229}3$

Finally,

$\displaystyle\int_C(x+9y)\,\mathrm dx+x^2\,\mathrm dy=108-\dfrac{229}3=\dfrac{95}3$

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3 years ago

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A sequence of transformations maps ∆ABC to ∆A′B′C′. The sequence of transformations that maps ∆ABC to ∆A′B′C′ is a reflection ac

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The correct answer is " (1) Reflect ABC across the x-axis and call this new triangle A'B'C'. (2) <span>Translate A'B'C' 2 units right and 6 units up so that its image is A''B''C''. "
</span>
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A in ABC is (1,9), B in ABC is (3,12), and C in ABC is (4,4).

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Both triangles are congruent. Since they are congruent, there are no contractions nor dilations occured. After rotating clockwise, we get A"C"B". So we need to reflect it to get A"B"C"

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