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2 years ago

PLEASE HELP

Mathematics

2 answers:

Nana76 [90]2 years ago

5 0

Answer = addition and multiplication

Goryan [66]2 years ago

4 0

Answer:

A. and C. Hope it helped brainiest plz

Step-by-step explanation:

Answer would be :

The set of whole numbers is closed by C. and A.

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Given the preimage and image,find the dilation scale factor.

Oliga [24]

Answer:

The dilation scale factor is $\frac{1}{2}$ .

Step-by-step explanation:

The image is the dilated form of its preimage if and only if the following conditions are observed:

1) $K' = \alpha_{1} \cdot K$

2) $T' = \alpha_{2} \cdot T$

3) $P' = \alpha_{3} \cdot P$

4) $J' = \alpha_{4} \cdot J$

5) $\alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}$

If we know that $K = (2, 0)$ , $K' = (1, 0)$ , $T = (3, 0)$ , $T' = (1.5,0)$ , $P = (1, 5)$ , $P' = (0.5, 2.5)$ , $J = (0, 3)$ and $J' = (0, 1.5)$ , then the coefficients are, respectively:

$\alpha_{1} = \frac{1}{2}$ , $\alpha_{2} = \frac{1}{2}$ , $\alpha_{3} = \frac{1}{2}$ , $\alpha_{4} = \frac{1}{2}$

As $\alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}$ , we conclude that the dilation scale factor applied in the preimage is equal to $\frac{1}{2}$ .

7 0

3 years ago

The cost of text books for school increases with the average class size identify the independent and dependent quantity in the s

Zinaida [17]

C average class size; cost

3 0

3 years ago

Read 2 more answers

Weight of a rock: In a geology course, students are learning to use a balance scale to accurately weigh rocks. One student plans

statuscvo [17]

Answer:

The student who weighted the rock 5 times has a 95% confidence interval of (25.2, 29.1) which is guaranteed to be more wider (less precise) than the other student who weighted the rock 20 times.

Step-by-step explanation:

What is Confidence Interval?

The confidence interval represents an interval that we can guarantee that the target variable will be within this interval for a given confidence level.

The confidence interval is given by

$CI = \bar{x} + t_{\alpha/2}(\frac{\sigma}{\sqrt{n} } ) \\$

Where $\bar{x}$ is the mean weight $\sigma$ is the standard deviation $t_{\alpha/2}$ is the critical value from t-table and n is the sample size.

The term $t_{\alpha/2}(\frac{\sigma}{\sqrt{n} } )$ is known as margin of error.

As the sample size is decreased the corresponding margin of error increases which results in wider confidence interval which means smaller precision.

The student who weighted the rock 5 times has a 95% confidence interval of (25.2, 29.1) which is guaranteed to be more wider (less precise) than the other student who weighted the rock 20 times.

We can say with 95% confidence that the true mean weight of the rock is within the interval of (25.2, 29.1).

7 0

2 years ago

Multiply (-8x - 9)(-9x2 + 7x - 9).

Misha Larkins [42]

= <span>(-8x - 9)(-9x2 + 7x - 9)

= 72x</span>³ - 56x² + 72x + 81x² - 63x + 81

= 72x³ + 25x² + 9x + 81

In short, Your Answer would be: Option D

Hope this helps!

3 0

3 years ago

Read 2 more answers

HELP PLEASE determine the number of real number solutions for the equation x^2+6x+9=0

brilliants [131]

Answer:

1 Answer->3

Step-by-step explanation:

To factor this out find the factors of 9 which add up to 6.

3 and 3 work therefore factor it out to

(x+3)(x+3)=0

Using Zero product property x is equal to -3

And there is only one answer which is 3

6 0

1 year ago