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neonofarm [45]
3 years ago
14

4 = 3а - 14 How do I solve this problem

Mathematics
2 answers:
kakasveta [241]3 years ago
8 0
3a-14=4
3a=4+14
3a=18
a=18/3
a=6
Simora [160]3 years ago
5 0

Answer:

X = 6

Step-by-step explanation:

Add 14 to both sides: 18 = 3a

Divide both sides by 3: a = 6

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4 years ago
Which of the following ways can be used to determine whether a linear relationship is proportional? Select all that apply.
svetlana [45]

Answer:

I think its b

Step-by-step explanation:

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6 0
3 years ago
A dormitory has n students, all of whom like to gossip. one of the students hears a rumor, and tells it to one of the other n −
Alekssandra [29.7K]

Answer:

P(r)=\frac{(n-3)(n-4)....(n-r)}{(n-2)^{r-2}}

Step-by-step explanation:

From the question, we have the following condition:

p_1=p_2=1,\:and\:p_n=0

We know that each student who hears the rumor tells it to a student picked at random from the dormitory (excluding, of course, himself/herself and the person from whom he/she heard the rumor)

The 3rd student can therefore tell the rumour to n-2 students but only n-3 will accept it.

\implies p(3)=\frac{n-3}{n-2}

Consequently, the 4th student must not tell the 1st and second students.

\implies p(4)=\frac{n-3}{n-2}\times \frac{n-4}{n-2}

We can rewrite this to observe a pattern:

\implies p(4)=\frac{(n-3)(n-4)}{(n-2)^2}

\implies p(4)=\frac{(n-3)(n-4)}{(n-2)^{4-2}}

\implies p(r)=\frac{(n-3)(n-4)(n-5)...(n-r)}{(n-2)^{r-2}}

Hence, the probability that the rumor is told r times without coming back to a student who has already is:

P(r)=\frac{(n-3)(n-4)....(n-r)}{(n-2)^{r-2}}

See attachment for complete question

4 0
4 years ago
At 6 a.m. the temperature was
ExtremeBDS [4]

Answer:

-6 degrees Fahrenheit

Step-by-step explanation:

Begginging temp: 26 degrees

Temp. dropped: 32 degrees

26 - 32 = -6 degrees

8 0
3 years ago
Does 20, 40, 30 form a pythagorean triple
Tatiana [17]

Answer:

Step-by-step explanation:

If it is a Pythagorean Triple the hypotenuse and the legs of a right triangle will all be integer values where

c^2=a^2+b^2

In this case, this isn’t even a right triangle as

20^2+30^2=40^2

400+900=1600

1300!=1600

because 1300 does not equal 1600 this is not a Pythagorean Triple.

6 0
3 years ago
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