Complete question :
Standardized tests: In a particular year, the mean score on the ACT test was 19.3 and the standard deviation was 5.3. The mean score on the SAT mathematics test was 532 and the standard deviation was 128. The distributions of both scores were approximately bell-shaped. Round the answers to at least two decimal places. Part: 0/4 Part 1 of 4 (a) Find the z-score for an ACT score of 26. The Z-score for an ACT score of 26 is
Answer:
1.26
Step-by-step explanation:
Given that:
For ACT:
Mean score, m = 19.3
Standard deviation, s = 5.3
Zscore for ACT score of 26;
Using the Zscore formula :
(x - mean) / standard deviation
x = 26
Zscore :
(26 - 19.3) / 5.3
= 6.7 / 5.3
= 1.2641509
= 1.26
Slowest- 5.665 because it is 5 so it will round up.
Fastest- 5.669 will also round up to the nearest hundredth which is 5.67
Answer:
For the student who is studying 10 hours a week is in the 57.93th percentile.
Step-by-step explanation:
Corresponding z-score for the student who studies 10 hours a week can be calculated by the formula
z=
where
- x is the hours student work in a week, which is 10,
- M is the mean studying hour of the class, which is 9.92,
- s is the standart deviation which is 4.54
from here we find that z=
≈0.2
Corresponding percentile for z=0.2 is 57.93
So, we have two equations. The first one is a/b = 2, and the other one is to find the value of 4b/a. In order to solve this, let's find the value of b/a. As you can observe, b/a is the reciprocal of a/b. Therefore, b/a is also the reciprocal of 2. This means that b/a = 1/2. Now, substituting this to the second equation, the answer would be
4b/a = 4(1/2) = 2
The answer is 2.
Step-by-step explanation:
This seems to be calculus 1.
<u>Question a</u>
We have 
m = slope = derivative
Find the derivative / slope of 
We do this by differentiating the polynomials. There are a few methods to do this but I am going to use the power rule, which we multiply the constant by the exponent on the variable and subtract one from the exponent.


when x = a
<em>Now that we have this information, we can answer question b</em>
<u>Question b</u>
<u>The tangent line for Point (1, 12)</u>
First find the slope by using our derivative.

Now that we have our slope, use point slope form to find our tangent line


<u>Now lets do the same for the Point (2, 13)</u>
Find the slope at the point.
Now find the tangent line using point slope form of a line.


Now graph the lines, which I have done and you can see by viewing the image I have attached.