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AVprozaik [17]
2 years ago
12

The management of Idaho Corporation is considering the purchase of a new machine costing $430,000. The company's desired rate of

return is 10%. The present value factors for $1 at compound interest of 10% for 1 through 5 years are 0.909, 0.826, 0.751, 0.683, and 0.621, respectively. In addition to the foregoing information, use the following data in determining the acceptability in this situation:
Year Income from Operations Net Cash Flow
1 $100,000 $180,000
2 40,000 120,000
3 20,000 100,000
4 10,000 90,000
5 10,000 90,000
The net present value for this investment is:
a. Negative $126,800
b. Negative $99,600
c. positive $16,400
d. positive $25,200
Business
1 answer:
rosijanka [135]2 years ago
4 0

Answer:

d. positive $25,200

Explanation:

The computation of the Net present value is shown below

= Present value of all yearly cash inflows after applying discount factor - initial investment

The discount factor should be computed by

= 1 ÷ (1 + rate) ^ years

where,  

rate is 10%  

Year = 0,1,2,3,4 and so on

Discount Factor:

Year 1 = 0.909

Year 2 = 0.826

Year 3 = 0.751

Year 4 = 0.683

Year 5 = 0.621

So, the calculation of a Present value of all yearly cash inflows are shown below

= Year 1 cash inflow × Present Factor of Year 1 + Year 2 cash inflow × Present Factor of Year 2 + Year 3 cash inflow × Present Factor of Year 3 + Year 4 cash inflow × Present Factor of Year 4 + Year 5 cash inflow × Present Factor of Year 5

= $180,000 × 0.909 + $120,000 × 0.826 + $100,000 × 0.751 + $90,000 × 0.683 + $90,000 × 0.621

= $163,620 + $99,120 + $75,100 + $61,470 + $55,890

= $455,200

So, the Net present value equals to

= $455,200 - $430,000

= $25,200

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Let the function of the revenue earned is given as

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  • r is the rate of interest which is 5% or 0.05
  • S(t) is the function of value which is S(t)=\left \{ {{66000t+38000} {\ \ 0So the equation becomes[tex]PV=\int\limits^0_1 {S(t)e^{-0.05t}} \, dt\\PV=\int\limits^{0.5}_0 {(66000t+38000)e^{-0.05t}} \, dt+\int\limits^{1}_{0.5}{(71000)e^{-0.05t}} \, dt\\PV=\int\limits^{0.5}_0 {(66000t)e^{-0.05t}} \, dt+\int\limits^{0.5}_0 {(38000)e^{-0.05t}} \, dt+\int\limits^{1}_{0.5}{(71000)e^{-0.05t}} \, dt\\PV=8113.7805+18764.4669+34207.6751\\PV=61085.9225

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    The present value is set equal to the value of machine which is given as

    $160,000 so the equation becomes:

    PV=61085.9225+\int\limits^{t}_{0}{(71000)e^{-0.05t}} \, dt\\160000=61085.9225+\int\limits^{t}_{0}{(71000)e^{-0.05t}} \, dt\\\int\limits^{t}_{0}{(71000)e^{-0.05t}} \, dt=160000-61085.9225\\\int\limits^{t}_{1}{(71000)e^{-0.05t}} \, dt=98914.07\\\\t=-\dfrac{\ln \left(0.93034\right)}{0.05}\\t=1.44496

    So the total time it would take to pay for its price is 2.44 years of 29.33 months.

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