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Talja [164]
4 years ago
15

Find any 3 irrational number between 2 by 3 and 4 by 5

Mathematics
2 answers:
FrozenT [24]4 years ago
7 0

Answer:

\sqrt{2}  \sqrt{3 }\sqrt{5} \\ irrational \: means \:has \: no \: square \: \\  root \:

Tatiana [17]4 years ago
4 0

Answer:

  • π/4 ≈ 0.785
  • e/4 ≈ 0.680
  • (√3) -1 ≈ 0.732

Step-by-step explanation:

It looks like you want irrational numbers between 2/3 ≈ 0.667 and 4/5 = 0.800.

Here are some:

  π/4 ≈ 0.785

  e/4 ≈ 0.680

  (√3) -1 ≈ 0.732

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PLEASE HELP FOR BRAINLIEST!!
LenaWriter [7]

Answer:

Slope = 1/5

Step-by-step explanation:

After plotting the points you do rise over run. 1/5 or 1 over 5 meaning you rise 1 and run across 5 to get to the next point

8 0
3 years ago
Find the basis for the subspace of R^3 spanned by S = {(81, 63, 12), (27, 21, 4), (9, 7, 1)). {(0, 0, 1), (9, 0, 0), (0, 7, 0);
Romashka-Z-Leto [24]

Answer with explanation:

A basis of a subspace in R³ is the set of vectors that spans the subspace means the set of vectors, and is linearly  independent.

The meaning of span is if any set of vectors can be written as linear combination of other vector.

For example , {a, b,c}, {p,q,r} and {x,y,z} are three set of vectors.

If ,{a,b,c} can be wriiten as {pm +x n, q m+y n, r m+z n}, then we say that  {a,b,c} spans the set of vectors.

1.

S={(81, 63, 12), (27, 21, 4), (9, 7, 1)}

Writing the set of vectors in matrix form

  \left[\begin{array}{ccc}81&63&12\\27&21&4\\9&7&1\end{array}\right]\\\\R_{2} \Rightarrow 3R_{2}-R_{1}\\\\R_{3} \Rightarrow 9R_{3}-R_{1}\\\\\left[\begin{array}{ccc}81&63&12\\0&0&0\\0&0&0\end{array}\right]

→Basis of S=1

As all the three vectors are linearly dependent.So, Basis=1.

2.

{(0, 0, 1), (9, 0, 0), (0, 7, 0)}

If you write these three vectors in matrix form , all the three vectors are Linearly Independent.Any of the one vectors can't be written as a linear combination of other

So, Basis =3

3.

{(1, 0, 0), (0, 0, 1), (0, 7, 0)}

All the three vectors are Linearly Independent.

So, Basis=3

4. {(0, 0, 1), (9,7, 0)}

These two vectors can't be written as a linear combination of other.So these two vectors are Independent.So,

Basis=2

5. {9,0,0), (0,7, 0)}

These two vectors can't be written as linear combination of each other.So these two vectors are Independent.So,

Basis=2

3 0
4 years ago
Carl is boarding a plane he has two checked bags of equal weight and backpack that weighs 4 kg the total weight of Carl’s backpa
Tresset [83]

Answer:

Carl's checked bags way 15.5 kilograms each.

Step-by-step explanation:

35-4=31 -> 31÷2=15.5

7 0
3 years ago
A bag contains 12 red marbles,14 yellow marbles, and 3 green marbles.
Simora [160]
0 because there are no blue marbles.
3 0
3 years ago
Which expressions are equivalent to the one below?check all that apply.
sineoko [7]
The answers for the question shown above are the option A, the option B and the option C, which are:
 A.log5(15625)
<span> B.log5(5^6)
 C.6
 The explanation is shown below:
 By applying the logarithms properties, you have:
 A. </span><span>log5(125)+log5(125)=log5(125)(125)=log5(15625)
 B. </span>log5(125)+log5(125)=log5(15625)=log5(5^6)
 C. og5(125)+log5(125)=log5(15625)=log5(5^6)=6log5(5)=6
3 0
3 years ago
Read 2 more answers
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