The equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1
<h3>Equation of a line</h3>
A line is the shortest distance between two points. The equation of a line in point-slope form and perpendicular to a line is given as;
y - y1 = -1/m(x-x1)
where
m is the slope
(x1, y1) is the intercept
Given the following
Point = (4, -1)
Line: 2x-y - 7 = 0
Determine the slope
-y = -2x + 7
y= 2x - 7
Slope = 2
Substitute
y+1 = -1/2(x -4)
Write in slope-intercept form
2(y + 1) = -(x - 4)
2y+2 = -x + 4
2y = -x + 2
y = -1/2 + 1
Hence the equation of a line passing through point (4, -1) and perpendicular to the line whose equation is 2x - y - 7 = 0 is y = -1/2x + 1
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The answer is A = 2 tenths
C = .2
A and C
Answer:
A,B,D
Step-by-step explanation:
Trust me just did it on edge
Answer:
x = −10 and x = 4
Step-by-step explanation:
x2 + 6x = 40
Subtract 40 from each side
x^2 + 6x -40 =0
Factor, what 2 numbers multiply to -40 and add to 6
10 * -4 = -40 10+-4 = 6
(x+10) (x-4) = 0
Using the zero product property
x+10 =0 x-4=0
x=-10 x=4
