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vladimir2022 [97]
4 years ago
9

The table shows the relationship between the number of Calories Jacob burns while roller skating and the number of minutes he ro

ller skates,
Minutes Calories Burned
40
200
80
400
120
600
160
800
How many calories will Jacob burn in 1 minute while roller-skating? Enter the answer in the box.
Mathematics
1 answer:
lianna [129]4 years ago
8 0

Answer: 5 calories

Step-by-step explanation:

Given the data:

Minute ____calorie burned

40__________200

80__________400

120_________ 600

160_________ 800

We need to find the rate at which calorie is burned :

Rate of burn = (Number of calorie burned/ time taken)

Take any of the points :

Time = 80 ; calorie burned = 400

Rate of burn = (400 calorie / 80 minute )

Rate of burn = 5calorie/minute

If time = 1 minute ; rate = 5

Calorie burned in 1 minute :

Amount of calorie = rate of burn × time taken

Amount burned in 1 minute = 5 × 1 = 5 calories

Hence, amount of calorie burned in one minute is 5 calories.

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aliina [53]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Plz help me on this its really hard :(
pickupchik [31]

Answer:

x = 11

Step-by-step explanation:

Equation:

(5x+1) + (12x-8) = 180

You are doing this because both sides on a straight line add up to 180 degrees. The two angles would add up to 180 degrees since they are on the one side of the line.

Simplifying:

(5x+12x) + (1-8) = 180

Add your common variables together; keep in mind that variables are placed before numbers.

Adding:

17x-7 = 180

Process:

To do this, you are going to simply do the opposite operation for the number without the variable on both sides of the equal sign.

17x - 7 = 180

     + 7    + 7

------------------

17x = 187

-----   ------

17       17

x = 11

You divided by 17 on both sides because you needed to get the x variable by itself. Hope this helped! :)

3 0
3 years ago
20 ÷ (5x2/5) + 3 help please​
vlabodo [156]

Answer:

13

Step-by-step explanation:

hey take a deep breath! you got this!

it's really simple if you use the format PEMDAS

P- parentheses

E-exponents

M-Muliplication

D-divison

A-addition

S-subtraction

or mostly used

P

E

M or D

A or S

(depends from which side just start Ex 2-1+8 you wouldn't do the plus first but the subtraction because we're going left to right. If it's 2x8-6+10 then we do multiplication first cause that step comes first, the minus then addition! hope that isn't to confusing!)

ok so our equation is 20÷(5x2/5)+3

whats our first step? remember PEMDAS!

Its Parenthesis! so first we do the equation (5x2/5)

since multiplication and division are in the same "category" we go left to right

so first we do 5x2=10 and then we do 10/5 which is equal to 2!

ok now we add back the rest of our equation!

20÷2+3 since we already solved the Parenthesis

now what come first? division or addition?

its division because.. once again... PEMDAS!!

So now we do 20÷2 which is equal to 10!

now whats left is to add 3!

and 10+3 is equal to .... 13!!!

I know it seems like a lot but you'll get the hang of it! just take it easy and take your time :)

8 0
2 years ago
Can a quadratic polynomial equation with real coefficients have one real solution and one complex solution? If so,
Anastasy [175]

Answer:

No

Step-by-step explanation:

We have to find that a quadratic polynomial equation with real coefficient can have one real solution and one complex solution.

quadratic equation is given by

ax^2+bx+c=0

It can be written as  the product of linear factors

ax^2+bx+c=a(x-r_1)(x-r_2)

Where r_1,r_2 are solutions of the given  polynomial equation.

No , a quadratic polynomial equation can not  have one real solution and one complex solution because complex root are always in paired not a single.

A quadratic equation have two roots only.

If a quadratic equation have complex root then the equation have both complex root .

If  a equation have real root then it have both real.

Therefore, a quadratic equation can not have one real and one compelx solution.

5 0
3 years ago
Factoring when a=1 x^2+4x-45
avanturin [10]

a=x^2+4x-45

a=(x+9)(x-5)

6 0
3 years ago
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