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quester [9]
4 years ago
5

Advice on how to make a smart home-buying decision

Advanced Placement (AP)
1 answer:
worty [1.4K]4 years ago
5 0
Don't get any smart home devices. Take it from me, many smart home devices are started to get into the IOT (Internet of Things) and that makes them prone to attacks via Wifi. 

Although any smart home stuff seems pretty cool, from a security standpoint it is just another way for people like me to control your life. 

Please message me on my profile if you would like to talk more about this. :) 
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All of the following are reasons to take dual enrollment courses except:
LenaWriter [7]
Why'd you post it if you already know the answer (C)
3 0
4 years ago
Read 2 more answers
When prices are (p1, p2) = (1, 2), a consumer demands (x1, x2) = (1, 2). When prices are (2,1), the consumer demands (2,1). Is t
BaLLatris [955]
<span>I think this is correct: (1) When prices are (p1, p2) = (1, 2) a consumer demands (x1, x2) = (1, 2),and when prices are (q1, q2) = (2, 1) the consumer demands (y1, y2) = (2, 1). I
 
(2) When prices are (p1, p2) = (2, 1) a consumer demands (x1, x2) = (1, 2),and when prices are (q1, q2) = (1, 2) the consumer demands (y1, y2) = (2, 1). 
Sorry if it's wrong</span>
8 0
3 years ago
Tabcorp provides wagering products via internet, mobile devices and phone?<br> True<br> False
Rina8888 [55]

Answer:

Tabcorp provides wagering products via internet, mobile devices and phone?

True

Explanation:

brainlies plsss

8 0
2 years ago
I can’t figure this problem out
Natalka [10]

Answer:

Explanation:

Alright so the way to do this is to use properties of integrals to make our life easier.

So we have:

\int\limits^4_1 {(3f(x)+2)} \, dx

So lets break this up into two different integrals that represent the same area.

\int\limits^4_0 {f(x)} \, dx - \int\limits^1_0 {f(x)} \, dx = \int\limits^4_1 {f(x)} \, dx

Lets think about what is going on up there. The integral from four to zero gives us the area under the curve of f(x) from four to zero. If we subtract this from the integral from one to zero (the area under f from one to zero) we are left with the area under f from four to one! Hence:

\int\limits^4_1 {f(x)} \, dx

But since we have these values we can say that:

-3 - 2 = -5

Which means that \int\limits^4_1 {f(x)} \, dx = -5

So now we can evaluate \int\limits^4_1 {(3f(x)+2)} \, dx

Lets first break up our integrand into two integrals

\int\limits^4_1 {(3f(x)+2)} \, dx = 3\int\limits^4_1{f(x)} \, dx + 2\int\limits^4_1 {} \, dx

Now we can evaluate this:

We know that \int\limits^4_1 {f(x)} \, dx = -5

So:

3(-5)+2[x] where x is evaluated at 4 to 1 so

-15 + 2(3)

So we are left with -15 + 6 = -9

5 0
3 years ago
Somebody tell me they fav rod wave song
vova2212 [387]
Hmmmmm just 5 points ☝ Heart on ice

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3 years ago
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