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bixtya [17]
4 years ago
15

Solve the equation 1/10 (x+108)=-2(6-x)

Mathematics
1 answer:
pav-90 [236]4 years ago
5 0

the answer is....x =12

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I confused ! I don't get what your trying to say please explain better !
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3 years ago
Find the area of an equilateral triangle with apothem 7 cm. Round to the nearest whole number.
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The answer is 255cm<span>²</span>
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3 years ago
Y''+Y'+Y=1<br> solve ordinary differential equation
taurus [48]

Answer:

y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1

Step-by-step explanation:

y" + y' + y = 1

This is a second order nonhomogenous differential equation with constant coefficients.

First, find the roots of the complementary solution.

y" + y' + y = 0

r² + r + 1 = 0

r = [ -1 ± √(1² − 4(1)(1)) ] / 2(1)

r = [ -1 ± √(1 − 4) ] / 2

r = -1/2 ± i√3/2

These roots are complex, so the complementary solution is:

y = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t)

Next, assume the particular solution has the form of the right hand side of the differential equation.  In this case, a constant.

y = c

Plug this into the differential equation and use undetermined coefficients to solve:

y" + y' + y = 1

0 + 0 + c = 1

c = 1

So the total solution is:

y(t) = c₁ e^(-1/2 t) cos(√3/2 t) + c₂ e^(-1/2 t) sin(√3/2 t) + 1

To solve for c₁ and c₂, you need to be given initial conditions.

5 0
3 years ago
Select the quadratic equation that has roots x=8 and x=-5
stellarik [79]

Step-by-step explanation:

Since, x=8 and x=-5 are the roots.

Therefore, (x - 8) & (x - 5) will be factors.

Hence, required quadratic equation can be given as:

(x - 8)(x - 5) =0 \\  \\  \therefore  {x}^{2}  + ( - 8 - 5) x+ ( - 8) \times ( - 5) = 0 \\  \\ \therefore  {x}^{2}  + ( - 13) x+ 40= 0  \\  \\ \huge \red{ \boxed{ \therefore  {x}^{2}  - 13x+ 40= 0 }} \\ is \: the \: required \: quadratic \: equation.

5 0
3 years ago
Given the explicit expression f(n)=4n+2, write a set showing the sequence.
Virty [35]

the answer is A because you would do 4x1+2 and then you would do 4x2+2 and so on

8 0
3 years ago
Read 2 more answers
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