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FinnZ [79.3K]
3 years ago
9

Excel Enterprises uses a Web​ site, online social​ networks, and print advertisements to promote its products. Since Excel Enter

prises practices integrated marketing​ communications, all these different brand contacts maintain​ ________ in design and tone.
Computers and Technology
2 answers:
7nadin3 [17]3 years ago
6 0

Answer:

The correct answer to the following question will be "Consistency".

Explanation:

Through combining branding correspondence, anyone can assume that somehow the various products operating underneath Excel Enterprises get the same basic structure, therefore the marketing department can probably sell certain functionality, despite having to set up multiple characters or guidelines per item.

  • This homogeneous layout eventually becomes comfortable for the consumer, a description of compatible architecture in the manual, as well as the tone is retained via the major products.
  • However when you switch between MS Excel to Word, they recognize that each program's use is specific, but perhaps the interface is always the same, helping yourself to understand the fundamentals of someone's UI, through knowing another.

So, it's the right answer.

Nuetrik [128]3 years ago
4 0

Answer:

Consistency

Explanation:

Bi integrating marketing communications, we can infer that the different brands working under Excel Enterprises have the same basic design, so the marketing department can sell their features easily, without having to create different campaigns or protocols for each individual product.

This homogeneous design then turns intuitive for the user, a textbook definition of consistent design, and the tone is maintained through the different brands.

Just like when you move from Microsoft's Excel to Microsoft's Word, you know the usage of each program is different, but the layout is the same, allowing you to understand the basics of the UX (user interface) of one, by understanding the other.  

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Nataly [62]

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2 years ago
____ involves taking data from your database and putting it into an electronic file in a format that another external applicatio
steposvetlana [31]

Answer:

The answer is "Option c".

Explanation:

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3 0
3 years ago
IMPORTANT HELP
balu736 [363]

Answer:

plz am so sorry I don't no it

Explanation:

Plz give me brainiest

6 0
3 years ago
Array, destination contains the number of 10 cities numbered 1 to 10 that the products were shipped to. Hence, 10 quantities of
Naddik [55]

Answer:

#include <stdlib.h>

#include <stdio.h>

void func1(int product[]){

int orders[6]={0};

for(int i=0;i<70;i++){

orders[product[i]]++;

}

printf("Total number of each type of products that were bought\n");

for(int i=1;i<=5;i++){

printf("Product %d = %d\n",i,orders[i]);

}

}

void func2(int product[],int quantity[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

total_cost+= price[product[i]]* quantity[i];

}

printf("The total cost of all 70 orders = %.2f\n",total_cost);

}

void func3(int product[],int quantity[],int destination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(destination[i]==8){

total_cost+= price[product[i]]* quantity[i];

}

}

printf("The total cost of all products shipped to destination 8 = %.2f\n",total_cost);

}

void func4(int product[],int quantity[],float price[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(price[product[i]]* quantity[i]>=50){

total_orders++;

}

}

printf("The total number of orders where each order is $50 or more = %d\n",total_orders);

}

void func5(int product[],int quantity[],int origination[],float price[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && price[product[i]]* quantity[i]>=50){

total_orders++;

}

}

printf("The total number of orders that originated from 3 where each order is $50 or more. = %d\n",total_orders);

}

void func6(int product[],int quantity[],int origination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && price[product[i]] * quantity[i]>=50){

total_cost += price[product[i]] * quantity[i];

}

}

printf("The total number of orders that originated from 3 where each order is $50 or more. = %.2f\n",total_cost);

}

void func7(int origination[],int destination[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && destination[i]==8){

total_orders++;

}

}

printf("The total number of orders that originated from 3 and shipped to 8. = %d\n",total_orders);

}

void func8(int product[],int quantity[],int origination[],int destination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(origination[i]==3 && destination[i]==8){

total_cost += price[product[i]] * quantity[i];

}

}

printf("The total cost of orders that originated from 3 and shipped to 8. = %.2f\n",total_cost);

}

void func9(int destination[]){

int total_orders=0;

for(int i=0;i<70;i++){

if(destination[i]!=8){

total_orders++;

}

}

printf("The total number of orders that was shipped to all destinations except to 8. = %d\n",total_orders);

}

void func10(int product[],int quantity[],int destination[],float price[]){

float total_cost=0;

for(int i=0;i<70;i++){

if(destination[i]!=8){

total_cost += price[product[i]] * quantity[i];;

}

}

printf("The total cost of orders that was shipped to all destinations except to 8. = %.2f\n",total_cost);

}

int main(){

int product[70] = {4, 2, 4, 2, 4, 5, 5, 2, 2, 5, 5, 4, 3, 5, 4, 2, 5, 3, 1, 2, 2, 3, 3, 4, 5, 5, 4, 5, 3, 5, 5, 1, 4, 5, 1, 5, 3, 2, 4, 1, 2, 4, 5, 1, 5, 5, 5, 5, 5, 2, 5, 1, 4, 4, 4, 2, 3, 3, 3, 3, 4, 3, 5, 5, 3, 2, 3, 5, 3, 2};

int quantity[70] = {10, 9, 6, 4, 10, 4, 9, 6, 10, 7, 3, 4, 4, 9, 1, 8, 9, 1, 5, 8, 7, 2, 3, 4, 10, 5, 6, 2, 1, 7, 2, 8, 6, 9, 8, 8, 7, 7, 9, 10, 6, 7, 8, 2, 1, 7, 6, 3, 3, 1, 8, 4, 10, 7, 1, 10, 6, 9, 8, 2, 4, 6, 1, 8, 2, 6, 10, 2, 6, 2};

int origination[70] = {2, 7, 5, 5, 7, 2, 7, 2, 7, 7, 5, 2, 5, 5, 5, 2, 2, 7, 2, 7, 7, 2, 2, 2, 2, 5, 7, 5, 7, 7, 5, 5, 2, 2, 5, 7, 2, 5, 7, 2, 5, 7, 2, 5, 7, 2, 2, 7, 2, 7, 5, 2, 2, 2, 5, 7, 2, 5, 5, 5, 7, 7, 2, 5, 2, 7, 5, 2, 5, 7};

int destination[70] = {8, 7, 3, 10, 2, 6, 4, 5, 1, 3, 5, 9, 5, 8, 6, 4, 3, 7, 1, 2, 7, 2, 8, 2, 2, 1, 2, 6, 10, 2, 7, 7, 8, 6, 8, 8, 4, 8, 3, 10, 6, 9, 4, 9, 5, 1, 7, 3, 1, 7, 5, 5, 4, 9, 3, 10, 8, 1, 1, 1, 1, 8, 10, 3, 5, 2, 8, 7, 4, 10};

float price[6]={0,11.95,7.95,19.95,24.95,15.25};

func1(product);

func2(product,quantity,price);

func3(product,quantity,destination,price);

func4(product,quantity,price);

func5(product,quantity,origination,price);

func6(product,quantity,origination,price);

func7(origination,destination);

func8(product,quantity,origination,destination,price);

func9(destination);

func10(product,quantity,destination,price);

}

Explanation:

The program inputs order, products and cities products are shipped.

After a series of conditional requirements being met, will output the destination each product os going to and the number of products with its associated price.

3 0
3 years ago
Read 2 more answers
A diet to contain at least 2400 units of vitamins, 1800 units of minerals, and 1200 calories two foods , Food A and Food B are t
Firdavs [7]

Answer:

30 units of Food A and 45 units of Food B are to be purchased to keep costs at the minimum $105.

Explanation:

X = Amount of food A

Y = Amount of food B

Z= 2X+Y..... minimum cost equation

50X + 20Y > 2400 .................Vitamins .......(1)

30X + 20Y > 1800 ...................Minerals.......(2)

10X + 40Y > 1200 .................Calories ..........(3)

X  > 0

y  > 0

X=30  and Y = 45

Z= 2(30) + 45 = $105

8 0
2 years ago
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