Mike takes a card out of his wallet at the grocery store and swipes it to pay for his groceries. What did Mike use?

An economy initially has 200 units of physical capital per worker. Each year, it increases the amount of physical capital by 10%

tatyana61 [14]

Answer:

266,2 units of capital per worker

Explanation:

The capital growth as stated is compound growth. Since technology and human capital are constant, there is not expected changed in productivity factors relationship, so the formula for compound growth, in this case, is: capital per worker in 3 years' time = capital per worker * (1+ annual rate growth) ^ 3. Computing numbers would be: capital per worker in 3 years' time = 200*(1+10)^3= 266,2

4 0

3 years ago

Hich correlation coefficient is one most likely to find between hours spent studying each week and cumulative gpa among college

8090 [49]

<u>".30"</u> is one most likely to find between hours spent studying each week and cumulative gpa among college students.

The correlation coefficient is a statistical measure that figures the quality of the connection between the relative developments of the two factors. The scope of qualities for the relationship coefficient limited by 1.0 on a flat out esteem premise or between - 1.0 to 1.0. In the event that the relationship coefficient is more prominent than 1.0 or not exactly - 1.0, the connection estimation is inaccurate. A connection of - 1.0 demonstrates an immaculate negative correlation, while a connection of 1.0 demonstrates a flawless positive correlation. A connection of 0.0 shows zero or no connection between the development of the two factors.

3 0

3 years ago

Oh, no! You contract Mononucleosis (Mono) and consequently miss two weeks of work without pay. You do not have any type of disab

Ilia_Sergeevich [38]

Answer:

Take a credit facility and do an insurance cover.

Explanation:

In order to meet your monthly financial commitments, you can seek for upfront credit facility through your organization if such provisions exist or ask for a salary loan which can be deducted from source (Salary).

To prepare for similar unfortunate incidence in the future, it will be important to secure a life and health insurance cover either through your organization or on an individual basis.

3 0

3 years ago

The Beef-up ranch feeds cattle for midwestern farmers and delivers them to processing plants in Topeka,Kansas and Tulsa, Oklahom

AfilCa [17]

Answer:

a. Min Z = 2x₁ + 2.50x₂ + 3x₃

Subject to constraints :

3x₁ + 2x₂ + 4x₃ ≤ 128 .......(1)

3x₁ + x₂ + 3x₃ ≤ 160 ........(2)

x₁ + 0x₂ + 2x₃ ≤ 32 .........(3)

6x₁ + 8x₂ + 4x₃ ≤ 256 .........(4)

3x₁ + 2x₂ + 4x₃ ≥ 64 ..........(5)

3x₁ + x₂ + 3x₃ ≥ 80 ..........(6)

x₁ + 0x₂ + 2x₃ ≥ 16 ...........(7)

6x₁ + 8x₂ + 4x₃ ≥ 128 ............(8)

x₁ ≤ 15 ...........(9)

x₂≤ 15 ...........(10)

x₃ ≤ 15 ...........(11)

x₁ , x₂, x₃ ≥ 0

b. x₁ = 15 , x₂ = 9.5 , x₃ = 8.5

c. The optimal solution is Z = 79.25

Explanation:

Given - The table is as follows :

Nutrient Feed 1 Feed 2 Feed 3
A 3 2 4
B 3 1 3
C 1 0 2
D 6 8 4

The minimum requirement per cow each month is 4 pounds of nutrient A, 5 pounds of nutrient B, 1 pound of nutrient C, and 8 pounds of nutrient D. However, cows should not be fed more than twice the minimum requirement for any nutrient each month. Additionally, the ranch can only obtain 1,500 pounds of each type of feed each month. Because there are usually 100 cows at the beef-up ranch at any given time, this means that no more than 15 pounds of each type of feed can be used per cow each month.

To find - a. Formulate a linear programming problem to determine how

much of each type of feed a cow should be fed each month.

b. Create a spreadsheet model for this problem, and solve it using

Solver.

c. What is the optimal solution?

Proof -

a.

Let feed 1 per cow per month = x₁

feed 2 per cow per month = x₂

feed 3 per cow per month = x₃

Now,

As given, The cost per pound of feeds 1,2, and 3 are $2.00, $2.50, and $3.00, respectively.

So, we have to minimize the cost , Z = 2x₁ + 2.50x₂ + 3x₃

Subject to constraints :

3x₁ + 2x₂ + 4x₃ ≤ 4(32)

3x₁ + x₂ + 3x₃ ≤ 5(32)

x₁ + 0x₂ + 2x₃ ≤ 1(32)

6x₁ + 8x₂ + 4x₃ ≤ 8(32)

∴ we get

Min Z = 2x₁ + 2.50x₂ + 3x₃

Subject to constraints :

3x₁ + 2x₂ + 4x₃ ≤ 128 .......(1)

3x₁ + x₂ + 3x₃ ≤ 160 ........(2)

x₁ + 0x₂ + 2x₃ ≤ 32 .........(3)

6x₁ + 8x₂ + 4x₃ ≤ 256 .........(4)

Now, as given

However, cows should not be fed more than twice the minimum requirement for any nutrient each month.

∴ we have

3x₁ + 2x₂ + 4x₃ ≥ $\frac{128}{2}$

3x₁ + x₂ + 3x₃ ≥ $\frac{160}{2}$

x₁ + 0x₂ + 2x₃ ≥ $\frac{32}{2}$

6x₁ + 8x₂ + 4x₃ ≥ $\frac{256}{2}$

and also

No more than 15 pounds of each type of feed can be used per cow each month.

⇒x₁ , x₂, x₃ ≤ 15

So,

The LPP model becomes

Min Z = 2x₁ + 2.50x₂ + 3x₃

Subject to constraints :

3x₁ + 2x₂ + 4x₃ ≤ 128 .......(1)

3x₁ + x₂ + 3x₃ ≤ 160 ........(2)

x₁ + 0x₂ + 2x₃ ≤ 32 .........(3)

6x₁ + 8x₂ + 4x₃ ≤ 256 .........(4)

3x₁ + 2x₂ + 4x₃ ≥ 64 ..........(5)

3x₁ + x₂ + 3x₃ ≥ 80 ..........(6)

x₁ + 0x₂ + 2x₃ ≥ 16 ...........(7)

6x₁ + 8x₂ + 4x₃ ≥ 128 ............(8)

x₁ ≤ 15 ...........(9)

x₂≤ 15 ...........(10)

x₃ ≤ 15 ...........(11)

x₁ , x₂, x₃ ≥ 0

b.)

We use simplex method calculator to solve this LPP Problem

we get

x₁ = 15 , x₂ = 9.5 , x₃ = 8.5

c.)

The optimal solution is Z = 79.25

4 0

2 years ago

What type of company can list and trade shares on the stock exchange?

Y_Kistochka [10]

The stock exchanges promote the orderly trading of stock shares of the companies that choose to list their shares with the different exchanges. There are over 5,000 companies listed on the two major U.S. stock exchanges: the New York Stock Exchange and the NASDAQ stock exchange.

hope this helps

5 0

3 years ago