Parent #1 has the alleles of IA and iParent #2 has the alleles of IB and iA punnet squares is a simple diagram that illustrates the possible genotypes of the offspring of these two people. Parent #1 is across the top and Parent #2 is along the side IA iIB AB IBii IAi ii
For IA or IB will be dominant to i. So for phenotype purposes their offspring have a 25% chande of being AB, 25% chance of B, 25% chance of A and a 25% change of type O (ii)
<span>HormonesNovaNet is the answer
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By process of elimination you can deduce the answer:
A mutation causing uncontrolled cell division in human tissue cells is cancer and definitely not beneficial.
A mutation resulting in partial or complete loss of chlorophyll pigments in plants will lead to a plant not being able to photosynthesise and therefore unable to respire leading to death.
A mutation resulting in a squirrel being born without ovaries means the squirrel will be unable to reproduce and there for is not beneficial.
The answer is therefore a mutation inhibiting human immunodeficiency virus from entering the host cell. This means that the person who has this gene is unable to contract HIV which is beneficial