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Bess [88]
3 years ago
14

Susan had a $10 coupon for the purchase of any time item. She bought a coat that was on sale for

Mathematics
1 answer:
gulaghasi [49]3 years ago
7 0
The original price is 260

2*125+10 please mark me brainliest
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The point (-3/5,y) in the third quadrant corresponds to angle θ on the unit circle.
romanna [79]
Sec(theta) = 1 / cos (theta) = hypotenuse / x -coordinate

hypotenuse = 1 (because it is the radius of the unit circle)

sec (theta) = 1 / (-3/5) = - 5/3

cot (theta) = 1 / tan(theta) = x-coordinate / y - coordinate

cot (theta) = -3/5 / y

y^2 + (-3/5)^2 = 1 => y^2 = 1 - 9/25 = 16/25 = y = +/- 4/5

Third quadrant => y = -4/5

=> cot (theta) = (-3/5) / (-4/5) = 3/4
7 0
3 years ago
If cos theta = 3/5 then tan theta =
algol13

Answer:

3 √5

Step-by-step explanation:

7 0
2 years ago
18 x 13 - 8 + 1,387 - 5,800,732,812 x 65
Mars2501 [29]

Answer:

(18x13)-8+1387-(5,800,732,812x65)= -377047631167

Step-by-step explanation:

3 0
2 years ago
What is the equation of a line that passes through the points (0,2) and (4,10)? Write your answer in slope-intercept form.
Vika [28.1K]

Answer:

y = -3x + 5

Step-by-step explanation:

7 0
2 years ago
They have a rectangle ABCD as shown below, where AB = 24cm BC = 10cm and AE = 13cm
alex41 [277]

Answer:

A. Area of ABCD = 240 cm^{2}

B. 60 cm

C. 36 cm

D. 50 cm

Step-by-step explanation:

Given: AB = 24cm BC = 10cm and AE = 13cm.

A.  Since a rectangle is a 2 dimensional figure, it has no volume but area.

So that,

the area of the rectangle ABCD = length x width

                                                     = 24 x 10

                                                     = 240 cm^{2}

B. To calculate the circumference of the BCD triangle, apply the Pythagoras theorem to determine BD.

BD^{2} = BC^{2} + DC^{2}

       = 10^{2} + 24^{2}

       = 676

BD = \sqrt{676}

     = 26

BD = 26 cm

so that,

the circumference of BCD = 10 + 24 + 26

                                         =   60 cm

C. To calculate the circumference of the BEC triangle,

AC = 26 cm, AE = 13 cm

CE = 26 - 13

     = 13 cm

CE = 13 cm

The circumference of the BEC triangle = 13 + 13 + 10

                                                                 = 36 cm

D. The circumference of the DEC triangle = 13 + 13 + 24

                                                                 = 50 cm

       

7 0
3 years ago
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