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3 years ago

When you multiply expressions with the same base, you ______ the exponents.

Mathematics

2 answers:

MAXImum [283]3 years ago

6 0

You need to add the exponents

Morgarella [4.7K]3 years ago

4 0

When you multiply expressions with the same base, you __ADD____ the exponents.

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PLEASE HELP!!!!!!!!

11Alexandr11 [23.1K]

Answer:

The answers would be:
7) y=-0.5x+2
8) y=-0.5x+2
9) y=0.6x-2
10) y=6x-4

Step-by-step explanation:

7 0

2 years ago

Who know how to get alot of coins in a day

Elan Coil [88]

Answer: You get a lot of coins by answering people's questions.

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3 years ago

Read 2 more answers

Which set of side lengths forms a right triangle? A) 5 cm, 6 cm,7 cm B) 2 cm, 4 cm, 6 cm C) 8 cm, 9 cm, 11 cm D) 8 cm, 15 cm, 17

Tamiku [17]

A) 5cm,6cm,7cm
you’re welcome

3 0

3 years ago

What is the height and length of a rectangular box with a volume of 6x^2-600 with a width of 6

harina [27]

Answer:

(x+10) and (x-10)

Step-by-step explanation:

The volume of a rectangular box is defined as

Volume = width*height*length

In this case

Volume = 6x^2-600 = 6*(x^2 - 100)

And we also know,

Volume = (6)*height*length

So,

6*(x^2 - 100) = (6)*height*length

This means that

height*length = (x^2 - 100)

height*length = (x+10)*(x-10)

7 0

3 years ago

Does anyone know the answer to these two questions? thank you.

tamaranim1 [39]

Problem 24

Part 1

$\displaystyle \int \csc(x)\left(\sin(x)+\cot(x)\right)dx\\\\\displaystyle \int \frac{1}{\sin(x)}\left(\sin(x)+\frac{\cos(x)}{\sin(x)}\right)dx\\\\\displaystyle \int \frac{1}{\sin(x)}*\sin(x)+\frac{1}{\sin(x)}*\frac{\cos(x)}{\sin(x)}dx\\\\\displaystyle \int 1+\frac{\cos(x)}{\sin^2(x)}dx\\\\\displaystyle \int 1 dx+\int \frac{\cos(x)}{\sin^2(x)}dx\\\\\displaystyle x+C_1+\int \frac{1}{u^2}du \ \text{ ... where } u = \sin(x)\\\\\displaystyle x+C_1+\int u^{-2}du\\\\$

Part 2

$\displaystyle x+C_1+\frac{1}{1+(-2)}u^{-2+1}+C_2\\\\\displaystyle x+C_1+\frac{1}{-1}u^{-1}+C_2\\\\\displaystyle x+C_1-u^{-1}+C_2\\\\\displaystyle x+C_1-\frac{1}{u}+C_2\\\\\displaystyle x+C_1-\frac{1}{\sin(x)}+C_2\\\\\displaystyle x-\frac{1}{\sin(x)}+C_1+C_2\\\\\displaystyle x-\frac{1}{\sin(x)}+C\\\\\displaystyle x-\csc(x)+C\\\\$

<h3>Answer: x - csc(x) + C</h3>

Don't forget about the plus C constant

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Problem 26

Fortunately, there aren't as many steps for this problem.

$\displaystyle \int \frac{dy}{\csc(y)}\\\\\displaystyle \int \frac{1}{\csc(y)}dy\\\\\displaystyle \int \sin(y)dy\\\\\displaystyle -\cos(y)+C\\\\$

<h3>Answer: -cos(y) + C</h3>

6 0

3 years ago