Let the first number be 'x' and the second number is 'y'
Equation 1: x + y = 52
Equation 2: x - y = 38
Rearranging equation 2 to make either x or y the subject
x = 38 + y
Substituting x = 38 + y into equation 1
x + y = 52
(38+y) + y = 52
38 + 2y = 52
2y = 52 - 38
2y = 14
y = 7
Substitute y = 7 into either equation 1 or equation 2 to find x
x + y = 52
x + 7 = 52
x = 52 - 7
x = 45
x = 45
y = 7
3/4 in = 6 mi
? In = 32 miles
32 * 0.74 / 6 = 4 in
The distance apart is 4 in
X: earn per hour during the week
y: earn per hour during the weekend
13x + 14y = 250.90
15x + 8y = 204.70
Multiply the first equation by 4 and the second equation by 7
52x + 56y = 1003.6
105x + 56y = 1432.90
Subtract the first equation from the second:
53x = 429.30
x = 429.30/ 53
x = 8.10
Solve any of the equation for y:
15x + 8y = 204.70
y = [204.70 - 15(8.10)]/8 = 10.40
y - x = 10.40 -8.10 = 2.30
Answer: she earns $2.30 per hour more during the weekend than during the week.
<span>Simplifying
17x2 + -12x = 0
Reorder the terms:
-12x + 17x2 = 0
Solving
-12x + 17x2 = 0
Solving for variable 'x'.
Factor out the Greatest Common Factor (GCF), 'x'.
x(-12 + 17x) = 0
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