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3 years ago

A customer calculated the cost of a new jacket, c, including a 7% sales

1 answer:

3 0

We can put it into one step by multiplying the cost by 1.07 which basically takes into account the old cost of the jacket and the tax

the expression is
original amount * decimal multiplier (1.07) = new amount

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A wagon train on the Oregon Trail averaged 17.3 miles each day across the plains. How far was the wagon train able to travel in

Makovka662 [10]

17.3 x 7 = 121.1 per week

121.1 x 4 = 484.4

5 0

3 years ago

Read 2 more answers

Could you explain how you got the answer to please

Zina [86]

Answer:

I think is 53 A

Step-by-step explanation:

6 0

3 years ago

Please help and give a explanation I will give brainliest and 25 points

Doss [256]

Answer:

Addition: -1 + -3 = -4

Subtraction: (-4) - 5 = -10

Step-by-step explanation:

Since adding a positive makes a negative number stay negative, it equals -4.

Then by subtracting a negative with a positive (5), the number stays negative once again, which then equals -10.

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3 years ago

Jenny and Natalie are selling cheesecakes for a school fundraiser. Customers can buy chocolate cakes and vanilla cakes. Jenny so

IrinaVladis [17]

The cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

Solution:

Let "c" be the cost of 1 chocolate cake

Let "v" be the cost of 1 vanilla cake

Jenny sold 14 chocolate cakes and 5 vanilla cakes for 119 dollars

Therefore, we can frame a equation as:

14 x cost of 1 chocolate cake + 5 x cost of 1 vanilla cake = 119

$14 \times c + 5 \times v=119$

14c + 5v = 119 ------- eqn 1

Natalie sold 10 chocolate cakes and 10 vanilla cakes for 130 dollars

Therefore, we can frame a equation as:

10 x cost of 1 chocolate cake + 10 x cost of 1 vanilla cake = 130

$10 \times c + 10 \times v = 130$

10c + 10v = 130 -------- eqn 2

Let us solve eqn 1 and eqn 2

Multiply eqn 1 by 2

28c + 10v = 238 ------ eqn 3

Subtract eqn 2 from eqn 3

28c + 10v = 238

10c + 10v = 130

( - ) --------------------------

18c = 108

c = 6

Substitute c = 6 in eqn 1

14(6) + 5v = 119

84 + 5v = 119

5v = 119 - 84

5v = 35

v = 7

Thus cost of 1 chocolate cake is $ 6 and cost of 1 vanilla cake is $ 7

8 0

3 years ago

Simply (6^5/7^3) ^2

Sav [38]

$\bf \left( \cfrac{6^5}{7^3} \right)^2\implies \left( \cfrac{6^{5\cdot 2}}{7^{3\cdot 2}} \right)\implies \cfrac{6^{10}}{7^6}\implies \cfrac{60466176}{117649}\implies 513\frac{112239}{117649}$

5 0

3 years ago