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Andreas93 [3]
2 years ago
15

What is the minimum value for the function shown in the graph? Enter your answer in the box.

Mathematics
1 answer:
SVEN [57.7K]2 years ago
5 0

Answer:

2.5.

Step-by-step explanation:

The value of f at the bottom of the loops.

You might be interested in
Five adult tickets and three child tickets for a movie costs £55. The cost of buying two adult tickets and three child tickets i
Allisa [31]

Answer:

  • adult £8
  • child £5

Step-by-step explanation:

If you look at the numbers you are given, you see that the first purchase has 3 more adult tickets than the second purchase, and its cost is £24 more. This means an adult ticket costs £24/3 = £8.

Two adult tickets will cost 2×£8 = £16, so three child tickets cost ...

  £31 -16 = £15

Each child ticket is then £15/3 = £5.

An adult ticket costs £8; a child ticket costs £5.

7 0
3 years ago
A couple intends to have two children, and suppose that approximately 52% of births are male and 48% are female.
Pachacha [2.7K]

a) Probability of both being males is 27%

b) Probability of both being females is 23%

c) Probability of having exactly one male and one female is 50%

Step-by-step explanation:

a)

The probability that the birth is a male can be written as

p(m) = 0.52 (which corresponds to 52%)

While the probability that the birth is a female can be written as

p(f) = 0.48 (which corresponds to 48%)

Here we want to calculate the probability that over  2 births, both are male. Since the two births are two independent events (the probability of the 2nd to be a male  does not depend on the fact that the 1st one is a male), then the probability of both being males is given by the product of the individual probabilities:

p(mm)=p(m)\cdot p(m)

And substituting, we find

p(mm)=0.52\cdot 0.52 = 0.27

So, 27%.

b)

In this case, we want to find the probability that both children are female, so the probability

p(ff)

As in the previous case, the probability of the 2nd child to be a female is independent from whether the 1st one is a male or a female: therefore, we can apply the rule for independent events, and this means that the probability that both children are females is the product of the individual probability of a child being a female:

p(ff)=p(f)\cdot p(f)

And substituting

p(f)=0.48

We find:

p(ff)=0.48\cdot 0.48=0.23

Which means 23%.

c)

In this case, we want to find the probability they have exactly one male and exactly one female child. This is given by the sum of two probabilities:

- The probability that 1st child is a male and 2nd child is a female, namely p(mf)

- The probability that 1st child is a female and 2nd child is a male, namely p(fm)

So, this probability is

p(mf Ufm)=p(mf)+p(fm)

We have:

p(mf)=p(m)\cdot p(f)=0.52\cdot 0.48=0.25

p(fm)=p(f)\cdot p(m)=0.48\cdot 0.52=0.25

Therefore, this probability is

p(mfUfm)=0.25+0.25=0.50

So, 50%.

Learn more about probabilities:

brainly.com/question/5751004

brainly.com/question/6649771

brainly.com/question/8799684

brainly.com/question/7888686

#LearnwithBrainly

5 0
3 years ago
What is the property of 93+(68+7)
adelina 88 [10]
Associative property is the answer.
5 0
4 years ago
Solve for X, 4x+5=17
Anettt [7]

Answer:

x=3

Step-by-step explanation:

4x=17-5

4x=12

x=4/12

x=3

7 0
3 years ago
Read 2 more answers
I’ll give you brainliest!
weeeeeb [17]

Answer:

2139m (total area)

Step-by-step explanation:

I am like 98% sure this is right

23* 31= 713 (1 side area)

713+713=1426 (2 sides area)

31-12=19 (middle height)

19*23= 437 (middle area)

437+1426=2139m (total area)

7 0
3 years ago
Read 2 more answers
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