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Savatey [412]
3 years ago
15

Please help!!!!!! (fill the blank)

Mathematics
2 answers:
Lady_Fox [76]3 years ago
6 0

Answer:

Volume fish foodcube = 0.015625 ft^3

Volume Shipping box= 42.1875 ft^3

Step-by-step explanation:

Volume Fish food cube: 1/4 × 1/4 × 1/4 = 0.015625

Volume Shipping Box: 15/4 × 15/4 × 12/4 = 42.1875

Can you put be Brainliest please if it helps

vovikov84 [41]3 years ago
5 0

It appears that your question contains either a link or inappropriate words. Please correct and submit again!

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What are the factors of 36
nasty-shy [4]
1,36. 2,18. 3,12. 4,9. 6,6. I thibk thats all
4 0
2 years ago
An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
3 years ago
Expand: -3(x – y + 5)​
HACTEHA [7]

Answer:

-3x+3y-15

Step-by-step explanation:

;)

5 0
2 years ago
Read 2 more answers
A culture of 100,000 bacteria triples every hour. How many bacteria were there 3 hours ago? (easy steps please)​
Crank

Answer:

If it multiplies by 3 each hour, you would divide by three if you are looking for the first term. It is Geometric Sequence.

Step-by-step explanation:

100,000/3=33333.3333333 (1/3)

5 0
3 years ago
What is the value of tan (-2pi/3)?
wolverine [178]
This revolves around exact trig values - no easy way to say this, you just need to memorise them. They are there for sin cos and tan, but I will give you the main tan ones below - note this is RADIANS (always work in them when you can, everything is better):

tan0: 0
tanpi/6: 1/sqrt(3) 
tanpi/4: 1
tanpi/3: sqrt(3)
tanpi/2: undefined

Now we just need to equate -2pi/3 to something we understand. 2pi/3 is 1/3 of the way round a circle, so -2pi/3 is 1/3 of the way round the circle going backwards (anticlockwise), so on a diagram we already know it's in the third quadrant of the circle (somewhere between pi and 3pi/2 rads).
We also know it is pi/3 away from pi, so we are looking at sqrt(3) or -sqrt(3) because of those exact values.

Now we just need to work out if it's positive or negative. You can look up a graph of tan and it'll show that the graph intercepts y at (0,0) and has a period of pi rads. Therefore between pi and 3pi/2 rads, the values of tan are positive. Therefore, this gives us our answer of sqrt(3).
4 0
3 years ago
Read 2 more answers
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