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Mrrafil [7]
3 years ago
14

The cone below has a radius of 3 inches, a height of 4 inches, and a slant height of 5 inches. What is the approximate lateral a

rea of the cone? Use 3.14 for π and round to the nearest whole number.
Mathematics
2 answers:
Andru [333]3 years ago
7 0

Answer:

47^2

Step-by-step explanation:

Natali [406]3 years ago
6 0
<span>Cone Lateral Area = (<span>π<span> • r •<span> slant height)
</span></span></span></span><span>Cone Lateral Area = (PI * 3 * 5)
</span>Cone Lateral Area = <span> <span> <span> 47.1 </span> </span> </span> square inches
Cone Lateral Area = <span> <span> 47</span></span> square inches (rounded to nearest whole number).


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What is the average rate of change of the function over the interval x = 0 to x = 6?
Ymorist [56]

Answer:

15 2/3, or 47/3

Step-by-step explanation:

I'm going to assume, correctly or not, that you actually meant f(x) = 2x^2 - (1/3)x + 5.  Double check on this right now, please.

If I'm right, then evaluate f(x) at x = 0 and x = 8:

f(0) = 5

and

f(8) = 2(8)^2 - (1/3)(8) + 5 = 128 - 8/3 + 5 = 133  - (2 2/3), or:   130 1/3

Then the average rate of change of f(x) = 2x^2 - (1/3)x + 5 over the interval [0,8] is:

               130 1/3 - 5         125 1/3

a. r. c. = ------------------- = ---------------- = 15 2/3, or 47/3

                    8 - 0                  8

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What is the total surface area of the cone? 90π cm2 65π cm2 120π cm2 115π cm2
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A researcher wants to determine whether the number of minutes adults spend online per day is related to gender. A random sample
suter [353]

Answer:

The expected frequency for the cell E2,2 is = 33

Step-by-step explanation:

The given data is

Gender               | 0-30| 30-60| 60-90| 90+       Totals

Male                    | 23    |    35   |   76    |  46        180

<u> Female               |   31   |    42   |   46    |  16         135    </u>

<u>Totals                    54         77        122    62          315  </u>

<u />

The expected frequency for the cell E2,2 is :

Expected for the (30-60 box for females)   =  Total of (30-6)/ (total )* females

                                                                      = ( 77/315)135= 33

Here p= 77/315 and n= 135

therefor X= pn = 33

χ²=  (33-42)²/33= 2.455  ( for the single value of E2,2=33)

Expected for the (30-60 box for males)   =  Total of (30-6)/ (total )* males

                                                                      = ( 77/315)180= 44

χ²=  (44-42)²/44= 0.09

The critical region is  χ² (0.05) 3 ≥  χ²= 11.34

Let the null and alternate hypothesis be

H0:the number of minutes spent online per day is not related to gender

against

Ha: the number of minutes spent online per day is related to gender

The single value of χ² for E2,2 = 2.45 is less than the critical value of 11.34.  

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