They need to sell 5 pieces to cover their expenditures (have a profit of zero).
<h3>
How many cakes will they have sold?</h3>
We know that the costs are:
- $30 for the booth at the fair.
- $2 for each piece of cake they sell.
And the revenue is:
- $8 for each piece of cake.
So, the profit (the difference between the revenue and the cost) for selling x pieces is:
p(x) = $8*x - $2*x - $30
p(x) = $6*x - $30
We want to find the value of x such that p(x) = 0, then:
0 = $6*x - $30
x = $30/$6 = 5
They need to sell 5 pieces to cover their expenditures (have a profit of zero).
If you want to learn more about profit:
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Answer:
going upp then downn
Step-by-step explanation:
We have to simplify
sec(θ) sin(θ) cot(θ)
Now first of all let's simplify these separately , using reciprocal identities.
Sec(θ) = 1/cos(θ)
Sin(θ) is already simplified
Cot(θ)= cos(θ) / sin(θ) ,
Let's plug these values in the expression
sec(θ) sin(θ) cot(θ)
= ( 1/cos(θ) ) * ( sin(θ) ) * ( cos(θ) / sin(θ) )
= ( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )
sin cancels out with sin and cos cancels out with cos
So , answer comes out to be
=( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )
= 1
D. The elevator takes 37.5 seconds to move down to the lobby.
8x+y=300
y= 300-8x
y= 300 - 8 (37.5)
y = 300-300
y = 0
wheb y =0 that means that the height is 0
